e swings a ball around him, in uniform circular motion. The circle's radius is r. George rtently releases the string, and the ball goes outward. He catches the string again, and now I goes around him at a new rotation rate, with a new radius r+ Ar. Calculate the new rotation n rev/s). 3.0 m = 0.5 m %3D iginal rotation rate = w; = 1.8 rev/s %3D %3D e ball's mass is m = 106 grams %3D

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Chapter1: Units, Trigonometry. And Vectors
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LS
George swings a ball around him, in uniform circular motion. The circle's radius is r. George
inadvertently releases the string, and the ball goes outward. He catches the string again, and now
the ball goes around him at a new rotation rate, with a new radius r+ Ar. Calculate the new rotation
rate (in rev/s).
• r = 3.0 m
Ar = 0.5 m
Original rotation rate = w; = 1.8 rev/s
106 grams
%3D
The ball's mass is m =
Transcribed Image Text:LS George swings a ball around him, in uniform circular motion. The circle's radius is r. George inadvertently releases the string, and the ball goes outward. He catches the string again, and now the ball goes around him at a new rotation rate, with a new radius r+ Ar. Calculate the new rotation rate (in rev/s). • r = 3.0 m Ar = 0.5 m Original rotation rate = w; = 1.8 rev/s 106 grams %3D The ball's mass is m =
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