e shear strength of each of ten test spot welds is determined, yielding the following data (psi). 373 415 375 358 409 371 397 389 362 367 (a) Assuming that shear strength is normally distributed, estimate the true average shear strength and standard deviation shear strength using the method of maximum likelihood. (Round your answers to two decimal places.) average 381.6 V psi standard deviation 19.84 x psi (b) Again assuming a normal distribution, estimate the strength value below which 95% of all welds will have their strengths. [Hint: What is the 95th percentile in terms of p and o? Now use the invariance principle.] (Round your answer to two decimal places.) psi (c) Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X S 400). [Hint: P(X S 400) = 0((400 - u)/o).] (Round your answer to four decimal places.)

e shear strength of each of ten test spot welds is determined, yielding the following data (psi). 373 415 375 358 409 371 397 389 362 367 (a) Assuming that shear strength is normally distributed, estimate the true average shear strength and standard deviation shear strength using the method of maximum likelihood. (Round your answers to two decimal places.) average 381.6 V psi standard deviation 19.84 x psi (b) Again assuming a normal distribution, estimate the strength value below which 95% of all welds will have their strengths. [Hint: What is the 95th percentile in terms of p and o? Now use the invariance principle.] (Round your answer to two decimal places.) psi (c) Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X S 400). [Hint: P(X S 400) = 0((400 - u)/o).] (Round your answer to four decimal places.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The torque, T(N.m), required to rotate shafts of different diameters, D(mm), on a machine is shown in the table below. If the low is: T = aD" where a and n are constants. Determine the constants a and n to give the best fit to following data: D (тm) | 7.0 T (N.m) 0.974 Then standard deviation (S,) about the mean. 10 1.71 25 18 4.33 40 15.3 7.28
A granular soil has an angle of friction with a mean value of 40° and a coefficient of variation of 2.5%. Determine the corresponding mean and standard deviations values for the bearing capacity coefficient, N..
The tensile adhesion of each of 20 randomly selected specimens of a metal tested. The resulting measurements (in megapascals). Use them to calculate a 90% condence interval for the true mean tensile adhesion strength of the metal. tensile adhesion of 20 specimens: 11.4 11.9 13.6 8.8 19.5 15.8 16.7 17.6 14.1 11.4 11.9 12.7 7.9 18.5 15.4 15.4 7.5 14.9 10.1 19.8 Using Excel, Total sum of 20 specimen measurements= 274.9 Average = 13.745 Use the given amounts to find the 90% confidence interval of the true mean.
Two types of force sensors (A and B) to measure the applied force (Ib) at the tip of a cantilever in a student Lab. The two data sets are shown below: 1. Standard N Deviation Average A 140.2 10.01 12 B 145.5 8.96 14 a. Estimate the interval of the true mean with 95% confidence, using data from sensor A. b. How many more measurements are needed for sensor A to have the same interval with 99% confidence (assume the mean and standard deviation are the same)? c. How many measurements (out of 12) using sensor A to have force greater 142 (randomly sampled)? d. What is the probability to have the true mean force greater 142 using sensor A? e. Determine if there is a difference between the two sensors A and B with 95% of confidence.
A person's body mass index (BMI) is computed by dividing the weight (kg) by the square of height (m). The accompanying table contains the BMI statistics for random samples of males and females. Assume that the two samples are independent simple random samples selected from normally distributedpopulations, and do not assume that the population standard deviations are equal. Let population 1 be females. Female BMI: n=69 x=29.14 s=7.41 Male BMI: n=79 x=28.18 s=5.24 The test statistic is The P-value is Construct a confidence interval appropriate for testing the claim in part (a). The ___% confidence interval estimate is ___<μ1−μ2<___.
The standard deviation of measurements of a linear dimension of a mechanical part is 0.14 mm. What sample size is required if the standard error of the mean must be no more than (a) 0.04 mm, (b) 0.02 mm?
The amount of lateral expansion (mils) was determined for a sample of n = 7 pulsed-power gas metal arc welds used in LNG ship containment tanks. The resulting sample standard deviation was s = 2.85 mils. Assuming normality, derive a 95% CI for oʻ and for o. (Round your answers to two decimal places.) CI for o? mils? CI for o mils
The compressive strength of concrete is normally distributed with u = 2507 psi and o = 51 psi. A random sample of n = 4 specimens is collected. What is the standard error of the sample mean? Round your final answer to three decimal places (e.g. 12.345). The standard error of the sample mean is psi.
The shear strength of each of ten test spot welds is determined, yielding the following data (psi). 402 360 389 364 415 375 367 409 362 358 (a) Assuming that shear strength is normally distributed, estimate the true average shear strength and standard deviation of shear strength using the method of maximum likelihood. (Round your answers to two decimal places.) average psi standard deviation psi (b) Again assuming a normal distribution, estimate the strength value below which 95% of all welds will have their strengths. [Hint: What is the 95th percentile in terms of µ and o? Now use the invariance principle.] (Round your answer to two decimal places.) psi (c) Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X < 400). [Hint: P(X < 400) = ¤((400 – µ)/).] (Round your answer to four decimal places.) You may need to use the appropriate table in the Appendix of Tables to answer this question.
The existing machine setting of a factory produces bearings with a diameter that is normally distributed with mean and standard deviation equal to 3.0005 cm and 0.0010 cm, respectively. Customer specifications require the bearing diameters to lie in the interval [2.998, 3.002]. Those outside the interval are considered scrap and must be re-machined. With the existing machine selling, what fraction of total production will not be considered scrap?
The amount of lateral expansion (mils) was determined for a sample of n = 5 pulsed-power gas metal arc welds used in LNG ship containment tanks. The resulting sample standard deviation was s = 2.84 mils. Assuming normality, derive a 95% CI for ² and for 6. (Round your answers to two decimal places.) CI for ² mils2 CI for o mils
A manufacturing company produces bearings. One line of bearings is specified to be 1.64 centimeters (cm) in diameter. A major customer requires that the variance of the bearings be no more than .001 cm². The producer is required to test the bearings before they are shipped, and so the diameters of 16 bearings are measured with a precise instrument, resulting in the following values. Assume bearing diameters are normally distributed. Use the data and a = 0.01 to test to determine whether the population of these bearings is to be rejected because of too high a variance. 1.68 1.62 1.63 1.70 1.66 1.63 1.65 1.71 1.64 1.69 1.57 1.64 1.59 1.66 1.63 1.65 Appendix A Statistical Tables (Round your answer to 2 decimal places, e.g. 15.25.) The value of the test statistic is and we reject the null hypothesis ⇒