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e same question as in the first photo. the answer from the second photo is correct, however i am also not allowed to use string indexing. is there any way i can still do the substitution cip

e same question as in the first photo. the answer from the second photo is correct, however i am also not allowed to use string indexing. is there any way i can still do the substitution cip

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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language: python so i still have the same question as in the first photo. the answer from the second photo is correct, however i am also not allowed to use string indexing. is there any way i can still do the substitution cipher in the most most most most most basic way?
ENGINEERING • COMPUTER-SCIENCE just need an advice language: python so I'm working on this substitution cipher where a user will input a statement plus randomized a-z letters. so the scenario goes like this: alphabet = abcdefghijklmnopqrstuvwxyz statement = abyz if the randomized a-z letters = qwertyuiopasdfghjklzxcvbnm then output should be: qwnm (q=a, w=b, e=c, and so on..). where every small caps letter on the statement excluding the punctuation marks or whatsoever, will be substituted with its equivalent in the randomized a-z letter. my problem is, i am limited to using only while loops, iterations, if-elif-else statements. i CANT use for loops, len(), lists, and other stuffs. any idea on how i can make my program work out? i've been thinking since earlier morning and over 24hrs later and i still cant figure it out.
Transcribed Image Text:ENGINEERING • COMPUTER-SCIENCE just need an advice language: python so I'm working on this substitution cipher where a user will input a statement plus randomized a-z letters. so the scenario goes like this: alphabet = abcdefghijklmnopqrstuvwxyz statement = abyz if the randomized a-z letters = qwertyuiopasdfghjklzxcvbnm then output should be: qwnm (q=a, w=b, e=c, and so on..). where every small caps letter on the statement excluding the punctuation marks or whatsoever, will be substituted with its equivalent in the randomized a-z letter. my problem is, i am limited to using only while loops, iterations, if-elif-else statements. i CANT use for loops, len(), lists, and other stuffs. any idea on how i can make my program work out? i've been thinking since earlier morning and over 24hrs later and i still cant figure it out.
Expert Answer o Step1 a) It can be solved using while loop only here is how it can be done: Step2 b) You can do something like this: alphabet = "abcdefghijklmnopqrstuvwxyz" #adding E just to know string is ended alphabet += 'E' letters = "qwertyuiopasdfghjklzxcvbnm" %3D i=0 #loop while string is ended while alphabet[i] != 'E': #end and flush is used to print in same line print(alphabet[i]+'=' + letters[i] + " ", end=", flush=True) i+= 1 Here is the output: a=q b=w c=e d=r e=t f=y g-u h=i i=o j=p k=a l=s m=d_n=f o=g p=h q=j r=k s=1 t=z u=x v=c w=V x=b y=n z=m
Transcribed Image Text:Expert Answer o Step1 a) It can be solved using while loop only here is how it can be done: Step2 b) You can do something like this: alphabet = "abcdefghijklmnopqrstuvwxyz" #adding E just to know string is ended alphabet += 'E' letters = "qwertyuiopasdfghjklzxcvbnm" %3D i=0 #loop while string is ended while alphabet[i] != 'E': #end and flush is used to print in same line print(alphabet[i]+'=' + letters[i] + " ", end=", flush=True) i+= 1 Here is the output: a=q b=w c=e d=r e=t f=y g-u h=i i=o j=p k=a l=s m=d_n=f o=g p=h q=j r=k s=1 t=z u=x v=c w=V x=b y=n z=m
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