E MZEFG = MZGDH = m/FEG = m/DHG = %3D F G

Please answer the three chart and show your work

If s = 4/t – 3, then %3D ds dt

The efficiency for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft?). An article gave the accompanying data on tank temperature (x) and efficiency ratio (y). Temp. 173 175 176 177 177 178 179 180 Ratio 0.94 1.21 1.44 1.05 1.09 1.02 0.96 1.88 Temp. 183 183 183 183 183 184 184 185 Ratio 1.53 1.50 1.57 2.07 2.05 0.86 1.53 0.80 Temp. 185 185 185 187 187 188 189 191 Ratio 1.71 1.96 2.76 1.59 2.60 3.10 1.81 3.18 In USE SALT (a) Determine the equation of the estimated regression line. (Round all numerical values to four decimal places.) (b) Calculate a point estimate for true average efficiency ratio when tank temperature is 185. (Round your answer to four decimal places.) (c) Calculate the values of the residuals from the least squares line for the four observations for which temperature is 185. (Round your answers to two decimal places.) (185, 0.80) (185, 1.71) (185, 1.96) (185, 2.76) Why do they not all have…

Differentiate with respect to x. Please show all steps.

2.2 7. pls help