Thelength of a bicycle pedal arm is 0.137 m, and a downward force of 126 N is applied to the pedal by the rider. What is the magnitudeof the torque about the pedal arm's pivot when the arm is at an angle of (a)37.2°, (b) 90°, and (c) 180° with the vertical?

Answered: Image /qna-images/answer/98b000c0-eca5-4a4e-a96e-6fcc582c77b2.jpg

e length of a bicycle pedal arm is 0.137 m, and a downward force of 126 N is applied to the pedal by the rider. What is the magnitude the torque about the pedal arm's pivot when the arm is at an angle of (a)37.2°, (b) 90°, and (c) 180° with the vertical?

e length of a bicycle pedal arm is 0.137 m, and a downward force of 126 N is applied to the pedal by the rider. What is the magnitude the torque about the pedal arm's pivot when the arm is at an angle of (a)37.2°, (b) 90°, and (c) 180° with the vertical?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

The figure below shows an angler with a fishing rod that makes an angle of 20.0° above the horizontal. The distance from the angler's hand to the tip of the rod isL = 2.18 m. A fish is on the line, and it pulls the line with a force of F = 109 N at an angle 37.0° below the horizontal. What is the magnitude of the torque (in N· m) exerted by the fish about an axis perpendicular to the page and passing through the angler's hand? 20.0° 37.0° I 20.0° N. m
A triangular plate is acted on by three forces, as in the figure. Taking the +z- direction to be out of the screen, calculate the net torque (magnitude and direction) about red point O if d₁ = 2.7 m, d₂ = 1.6 m, F₁ = 27 N, F₂ = 47 N, F3 = 52 N, 02 = 57°, and 03 = 45°. F3 03 27 = d₂ 102 k N.m F2 d₁ F₁
During the launch from a board, a diver's angular speed about her center of mass changes from zero to 6.90 rad/s in 310 ms. Her rotational inertia about her center of mass is 12.0 kg · m2. (a) During the launch, what was the magnitude of her average angular acceleration? rad/s2 (b) During the launch, what was the magnitude of the average external torque on her from the board? N. m
A rigid body rotates about a fixed axis with a constant angular velocity. Which one of the following statements is true concerning the tangential acceleration of any point on the body? O The tangential acceleration is zero m/s². The tangential acceleration does not depend on the angular velocity. O The tangential acceleration depends on the change in the centripetal acceleration. O The tangential acceleration is constant, but not equal to zero m/s², in both magnitude and direction. O The tangential acceleration is equal to the centripetal acceleration.
A gardener is using a tool as shown in the figure to pull weeds. You will notice that the tool is designed with a built in pivot point about which the torques are applied. If the gardener applies a 3.04-N · m torque (about the pivot point) in order to pull a weed, determine the resistive force the weed exerts on the weed puller. N 24 cm 6.0 cm
A worker opens a 1.50 m wide door by pushing on it with a force of 39.5 N directed perpendicular to its surface. ENT (a) What magnitude torque (in N. m) does she apply about an axis through the hinges if the force is applied at the center of the door? N.m (b) What magnitude torque (in N. m) does she apply at the edge farthest from the hinges? N. m
Force F2 acts half as far from the pivot as F1. What magnitude of F2 causes the net torque on the rod to be zero?
A uniform rod is set up so that it can rotate about an axis at perpendicular to one of its ends. The length and mass of the rod are 0.701 m and 1.29 kg , respectively. A force of constant magnitude ?F acts on the rod at the end opposite the rotation axis. The direction of the force is perpendicular to both the rod's length and the rotation axis. Calculate the value of ?F that will accelerate the rod from rest to an angular speed of 6.59 rad/s in 8.95 s.
(You cannot use Newton's second law or kinematics.) O Applied force The figure is a bird's eye view of a horizontal disc, which can rotate about a vertical axis through its center. The radius of the disc is 0.5 meter and its rotational inertia about the rotation axis is 10-3 kg.m². The torque due to friction in the rotation axis is constant, with magnitude 0.70 Nm. A constant horizontal force is continuously applied tangentially to the rim of the disc. The disc is initially at rest. The angular displacement of the disc is 4.0 rad and its angular speed is 90 rad/s at time T. There is no air drag. Calculate the magnitude of the applied force. (You cannot use Newton's second law or kinematics.)
A solid cylindrical disk has a radius of 0.12 m. It is mounted to an axle that is perpendicular to the circular end of the disk at its center. When a 40-N force is applied tangentially to the disk, perpendicular to the radius, the disk acquires an angular acceleration of 100 rad/s2. What is the mass of the disk? kg
A circular disk with a radius of 0.38 m is subject to 2 tangentially applied forces. The disc is fixed such that it will rotate about its center. Both forces produce a torque in the same direction. F1 = 3.5 N applied at the outer edge of the disc. F2 = 3.2 N applied at a distance of 0.28 from the center of the disc. What is the net torque on the disc?
A uniform, 267 N rod that is 2.06 mm long carries a 225 N weight at its right end and an unknown weight WW toward the left end (see the figure below). When WW is placed 55.9 cm from the left end of the rod, the system just balances horizontally when the fulcrum is located 74.7 cm from the right end. a. What is w (in N)? b. If the weight w is moved 25.3 cm to the right, how far must the fulcrum (balance point) be moved to restore balance? 225 N Figure 1. A mass rests on the left side of a balance beam.