e f] b c If det d e f a 15 then det a b c %3! h i h i

Given that $\det \left[\begin{array}{ccc}a& b& c\\ d& e& f\\ g& h& i\end{array}\right]=-15$

We have to find the $\det \left[\begin{array}{ccc}d& e& f\\ a& b& c\\ g& h& i\end{array}\right]$

Use the determinant property:- If any two row (or two column) of a determinant are interchanged the value of the determinant is multiplied by $-1$.

$\det \left[\begin{array}{ccc}d& e& f\\ a& b& c\\ g& h& i\end{array}\right]=\left(-1\right)\cdot \det \left[\begin{array}{ccc}a& b& c\\ d& e& f\\ g& h& i\end{array}\right]$........(1)