I don't understand how E = 5!*5!+5!*5!. I understand that E is equal to the number of ways 2 of the same genders can sit next to each other. Can you explain the logic and how my professor got E= 5!*5!+5!*5! ? E(2) If 5 boys and 5 girls sit in a row randomly, what is the probability notwo children of the same gender sit next to each other?odwd arrangementsчто5: the total Ħ#S#E110!5 !· 5! + 5 1512.51PLEIBE#SS126

The information provided in the question are as follows : Number of boys = 5 And Number of girls =…

E (2) If 5 boys and 5 girls sit in a row randomly, what is the probability no two children of the same gender sit next to each other? ordwed arrangements 2.10 S: the total # 10!! 5!*5! + 5151 #S #E PLEI ๆ BE #(S 2.51.11 1 - 126

E (2) If 5 boys and 5 girls sit in a row randomly, what is the probability no two children of the same gender sit next to each other? ordwed arrangements 2.10 S: the total # 10!! 5!*5! + 5151 #S #E PLEI ๆ BE #(S 2.51.11 1 - 126

College Algebra (MindTap Course List)

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter8: Sequences, Series, And Probability

Section8.CR: Chapter Review

Problem 80E

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Question

I don't understand how E = 5!*5!+5!*5!. I understand that E is equal to the number of ways 2 of the same genders can sit next to each other. Can you explain the logic and how my professor got E= 5!*5!+5!*5! ?