Introductory Circuit Analysis (13th Edition)
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ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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solve the network below
![**Circuit Diagram:**
The circuit consists of three parallel branches connected to an AC source with the following components:
1. **AC Source:**
- Voltage: \( E = 120 \, \text{V} \, \angle 0^\circ \)
- Frequency: \( f = 2 \, \text{kHz} \)
2. **Branch R1:**
- Resistor \( R_1 = 2 \, \Omega \)
3. **Branch R2-L:**
- Resistor \( R_2 = 200 \, \Omega \)
- Inductor \( L = 80 \, \text{mH} \)
4. **Branch C:**
- Capacitor \( C = 0.02 \, \mu\text{F} \)
The circuit diagram depicts these components arranged in parallel, underlining that they are connected directly across the power supply.
**Power Calculations:**
The task is to determine the total complex, apparent, real, and reactive power for each parallel branch.
**Branch R1 Calculations:**
- Complex Power (S):
- \( S = \) [Magnitude] \( \angle \) [Phase angle]
- \( S = \) [Real part] \( + j \) [Imaginary part]
- Apparent Power (\(|S|\)):
- Real Power (\(P\)):
- Reactive Power (\(Q\)):
**Branch R2-L Calculations:**
- Complex Power (S):
- \( S = \) [Magnitude] \( \angle \) [Phase angle]
- \( S = \) [Real part] \( + j \) [Imaginary part]
- Apparent Power (\(|S|\)):
- Real Power (\(P\)):
- Reactive Power (\(Q\)):
**Branch C Calculations:**
- Complex Power (S):
- \( S = \) [Magnitude] \( \angle \) [Phase angle]
- \( S = \) [Real part] \( + j \) [Imaginary part]
- Apparent Power (\(|S|\)):
- Real Power (\(P\)):
- Reactive Power (\(Q\)):
Populate the filled-in values for each calculation with appropriate units (e.g., volt-amperes, watts, vars).](https://content.bartleby.com/qna-images/question/945ae690-9b29-4664-b591-03f86d69ed48/4c217157-7151-45b9-8b38-0ef4135ecb0c/ir17w1_processed.png)
Transcribed Image Text:**Circuit Diagram:**
The circuit consists of three parallel branches connected to an AC source with the following components:
1. **AC Source:**
- Voltage: \( E = 120 \, \text{V} \, \angle 0^\circ \)
- Frequency: \( f = 2 \, \text{kHz} \)
2. **Branch R1:**
- Resistor \( R_1 = 2 \, \Omega \)
3. **Branch R2-L:**
- Resistor \( R_2 = 200 \, \Omega \)
- Inductor \( L = 80 \, \text{mH} \)
4. **Branch C:**
- Capacitor \( C = 0.02 \, \mu\text{F} \)
The circuit diagram depicts these components arranged in parallel, underlining that they are connected directly across the power supply.
**Power Calculations:**
The task is to determine the total complex, apparent, real, and reactive power for each parallel branch.
**Branch R1 Calculations:**
- Complex Power (S):
- \( S = \) [Magnitude] \( \angle \) [Phase angle]
- \( S = \) [Real part] \( + j \) [Imaginary part]
- Apparent Power (\(|S|\)):
- Real Power (\(P\)):
- Reactive Power (\(Q\)):
**Branch R2-L Calculations:**
- Complex Power (S):
- \( S = \) [Magnitude] \( \angle \) [Phase angle]
- \( S = \) [Real part] \( + j \) [Imaginary part]
- Apparent Power (\(|S|\)):
- Real Power (\(P\)):
- Reactive Power (\(Q\)):
**Branch C Calculations:**
- Complex Power (S):
- \( S = \) [Magnitude] \( \angle \) [Phase angle]
- \( S = \) [Real part] \( + j \) [Imaginary part]
- Apparent Power (\(|S|\)):
- Real Power (\(P\)):
- Reactive Power (\(Q\)):
Populate the filled-in values for each calculation with appropriate units (e.g., volt-amperes, watts, vars).
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- Let the following electrical circuits be, in which it is required to determine the value of the voltage V shown:Note that the two previous circuits are identical, the only difference is the load element that has been selected in each of them: in electrical network 1 the load element is resistor R3 while in electrical network 2 the element of load is resistor R1.a) Find, using Thévenin's theorem, the voltage V in electrical network 1.b) Find, using Thévenin's theorem, the voltage V in the electrical network 2.arrow_forwardPls helparrow_forwardProblem #14. Find V2.arrow_forward
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