Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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**Problem Statement:**

Find \(\frac{dy}{dx}\) for the given function.

\[ y = \frac{\csc(x)}{x} \]

**Solution:**

Evaluate \(\frac{dy}{dx}\):

\[ \frac{dy}{dx} = \boxed{\phantom{}} \]

**Explanation:**

This problem involves finding the derivative of a function expressed as a quotient. The function \( y = \frac{\csc(x)}{x} \) involves the cosecant function and the variable \( x \). Solving this requires using the quotient rule, which states that for two functions \( u(x) \) and \( v(x) \), the derivative of their quotient is:

\[ \frac{d}{dx}\left(\frac{u}{v}\right) = \frac{v(u') - u(v')}{v^2} \]

In this case, \( u(x) = \csc(x) \) and \( v(x) = x \). Apply the quotient rule to solve for \(\frac{dy}{dx}\).
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Transcribed Image Text:**Problem Statement:** Find \(\frac{dy}{dx}\) for the given function. \[ y = \frac{\csc(x)}{x} \] **Solution:** Evaluate \(\frac{dy}{dx}\): \[ \frac{dy}{dx} = \boxed{\phantom{}} \] **Explanation:** This problem involves finding the derivative of a function expressed as a quotient. The function \( y = \frac{\csc(x)}{x} \) involves the cosecant function and the variable \( x \). Solving this requires using the quotient rule, which states that for two functions \( u(x) \) and \( v(x) \), the derivative of their quotient is: \[ \frac{d}{dx}\left(\frac{u}{v}\right) = \frac{v(u') - u(v')}{v^2} \] In this case, \( u(x) = \csc(x) \) and \( v(x) = x \). Apply the quotient rule to solve for \(\frac{dy}{dx}\).
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