dv g) tan(x- y) = y 1+x² d 1/₂ (tan ex-x) = $x (1+x) dx dx Sec² (x-y). (1-dy) = dx Sec ³ (x-y) - dy + d sec² (x-y) · —— (x²-y) = (1 + x) · ** - Y- £x (1-x) dy dx (1+x²) Sec²³(x-1). dx = dy dx (1+x²³² = (1+x). Jy - y. (0 +ax) (1+x). (1+x) (1+x² + sec ³ (x-1)). 2 sec³(x-4) + 2xy sec ³ (x-Y). dy Jx = dr 1 Final Answe Seca Ix-X + Se. dy (1 + x²³) Jx = seca (x-y)+ axy Cit dy = sel³ (x-1) + axy. Se (1+x) - CI
dv g) tan(x- y) = y 1+x² d 1/₂ (tan ex-x) = $x (1+x) dx dx Sec² (x-y). (1-dy) = dx Sec ³ (x-y) - dy + d sec² (x-y) · —— (x²-y) = (1 + x) · ** - Y- £x (1-x) dy dx (1+x²) Sec²³(x-1). dx = dy dx (1+x²³² = (1+x). Jy - y. (0 +ax) (1+x). (1+x) (1+x² + sec ³ (x-1)). 2 sec³(x-4) + 2xy sec ³ (x-Y). dy Jx = dr 1 Final Answe Seca Ix-X + Se. dy (1 + x²³) Jx = seca (x-y)+ axy Cit dy = sel³ (x-1) + axy. Se (1+x) - CI
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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