During an electrolysis experiment, the following species are present in solution: H+, CH3COOH, CH3COO-, Na+, SO42-, H2O. The lead electrode dipped in the solution serves as the anode. Why can't the polyatomic anion SO42- be oxidized in this experiment?     because sulfur in this anion has its highest possible oxidation number of +6     because sulfur in this anion cannot give up any more electrons     because SO42- cannot act as a reducing agent     all statements above are correct

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During an electrolysis experiment, the following species are present in solution: H+, CH3COOH, CH3COO-, Na+, SO42-, H2O. The lead electrode dipped in the solution serves as the anode.

Why can't the polyatomic anion SO42- be oxidized in this experiment?

   

because sulfur in this anion has its highest possible oxidation number of +6

   

because sulfur in this anion cannot give up any more electrons

   

because SO42- cannot act as a reducing agent

   

all statements above are correct

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