duEach integration requires a simple substitution. Let u = 4y + 3 and v= 8x + 9. Then dy =41√ (4y + 3)²dy =1/12/20·]du =-u-¹ + C₁-(4y + 3)-¹ + C₁=1(8x + 9)²1/1/201818dvdx) v- 1 + C₂)(8x + 9)-1 + C₂and dx =dvTo finish, replace the constant C₂ C₁ by C to write the general solution to the given differential equation.

Answered: Image /qna-images/answer/2cff40aa-3c2e-46d9-9e69-791b076aaae0.jpg

du Each integration requires a simple substitution. Let u = 4y + 3 and v = 8x + 9. Then dy = 4 1 √ (4y + 3)² dy = ²1/12/20 du = - 1²/27/1/20 dv -1-¹+₁=(-1/2) (4y + 3)-¹ + C₁ J = 1 (8x + 9)² 8 1 8 dx )x= 1 + C₂ )(8x + 9)-¹ + C₂ and dx = dv To finish, replace the constant C₂ C₁ by C to write the general solution to the given differential equation.

du Each integration requires a simple substitution. Let u = 4y + 3 and v = 8x + 9. Then dy = 4 1 √ (4y + 3)² dy = ²1/12/20 du = - 1²/27/1/20 dv -1-¹+₁=(-1/2) (4y + 3)-¹ + C₁ J = 1 (8x + 9)² 8 1 8 dx )x= 1 + C₂ )(8x + 9)-¹ + C₂ and dx = dv To finish, replace the constant C₂ C₁ by C to write the general solution to the given differential equation.

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter2: Equations And Inequalities

Section2.3: Quadratic Equations

Problem 82E

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