Draw the Thevenin and Norton equivalents of the circuit

12 V 692 2 A 592 392 492 12 92 = The mesh-current equation of mesh 3 in the above circuit is (note: mesh 3 is the mesh where i3 is defined) O-311-512 + 2013 - 12i4 = 0 O-512 + 2013 - 1214 0 19 V -3i1 - 5i2 + 2013 + 1214 = 0 3i1512 + 20i3 124 0 =

7. For the circuit shown below, determine the Norton equivalent circuit as seen by the load resistance R3 between points A & B vl 25 V R1 3.5kg R2 6kg A B >R3 2kQ R Load.

Find the Thévenin voltage (also known as the open-circuit voltage). Do this by removing the load resistor.

Find the Thevenin equivalent when viewed from the ab-ends of the circuit given below. What is the Vth Thevenin voltage value in this case?

how do you find the the Norton equivalent of the circuit? and how do you use source transformation to find the Thevenin equivalent?

H. Use the superposition theorem to find the current in R₂- R3 R E₂ -lov 422 *** T *HEX EVİNİRİKčahan angepass 622 R₂ 352 432 Chan AND eraries

Consider the network shown in figure a 2002 ww LA :10Ω ww b +25V The Norton's equivalent model of the circuit across Ris (A) = 1.25 A and R = 8W N (B) I=0.8 A and R = 8W N N N (C) = 1.25 A and R₁ = 6W (D) IN=0.8 A and R₁ = 6W

Use mesh-current method to find v2 for the current shown

Required information Consider the circuit given in the figure. Take Vs = 20 V. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. 4 A 4Ω 2Ω 2 A 6Ω www + Vs b R₁ For the circuit, obtain the Thevenin equivalent at terminals a-b. The value of RTh is and the value of VThis V.