Draw the Lewis structure for the xenon tetrafluoride (XeF4) molecule.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Drawing the Lewis Structure for Xenon Tetrafluoride (XeF₄)**

Welcome to our interactive learning session on the Lewis structures of molecules! Today, we will focus on drawing the Lewis structure for xenon tetrafluoride (XeF₄).

### Step-by-Step Guide

1. **Identify the Total Number of Valence Electrons:**
   - Xenon (Xe) has 8 valence electrons.
   - Each fluorine (F) atom has 7 valence electrons.
   - Total number of valence electrons in XeF₄: 
     \( 1 \, \text{Xe} \times 8 \, \text{electrons} + 4 \, \text{F} \times 7 \, \text{electrons} = 8 + 28 = 36 \, \text{electrons} \).

2. **Draw the Skeleton Structure:**
   - Place the least electronegative atom (Xe) in the center.
   - Attach the four fluorine atoms to the xenon atom using single bonds.

3. **Distribute the Remaining Electrons:**
   - Each single bond (X-F) requires 2 electrons, thus, 4 bonds use \( 4 \times 2 = 8 \) electrons.
   - Subtract the bonded electrons from the total valence electrons: \( 36 - 8 = 28 \) electrons remaining.
   - Distribute these remaining 28 electrons around the fluorine atoms, ensuring each fluorine receives 8 electrons to complete its octet (bonding pair + lone pairs).

4. **Distribute Lone Pairs to Central Atom:**
   - After satisfying the octets of the fluorine atoms, any remaining electrons are placed on the central xenon atom.
   - Xenon can accommodate more than 8 electrons (expanded octet) because it is in Period 5 of the periodic table.

### Diagram Tools

- There is an interactive canvas on the right with tools for drawing:
  - **Bond Tool (single bond):** Used to draw bonds between atoms.
  - **Lone Pair Electron Tool:** Used for adding lone pairs to atoms.
  - **Erase Tool:** For correcting mistakes.
  - **Undo Button:** To revert the last action.
  - **Help Button (? symbol):** Access help documentation.

These tools will aid in accurately representing the Lewis structure of XeF
Transcribed Image Text:**Drawing the Lewis Structure for Xenon Tetrafluoride (XeF₄)** Welcome to our interactive learning session on the Lewis structures of molecules! Today, we will focus on drawing the Lewis structure for xenon tetrafluoride (XeF₄). ### Step-by-Step Guide 1. **Identify the Total Number of Valence Electrons:** - Xenon (Xe) has 8 valence electrons. - Each fluorine (F) atom has 7 valence electrons. - Total number of valence electrons in XeF₄: \( 1 \, \text{Xe} \times 8 \, \text{electrons} + 4 \, \text{F} \times 7 \, \text{electrons} = 8 + 28 = 36 \, \text{electrons} \). 2. **Draw the Skeleton Structure:** - Place the least electronegative atom (Xe) in the center. - Attach the four fluorine atoms to the xenon atom using single bonds. 3. **Distribute the Remaining Electrons:** - Each single bond (X-F) requires 2 electrons, thus, 4 bonds use \( 4 \times 2 = 8 \) electrons. - Subtract the bonded electrons from the total valence electrons: \( 36 - 8 = 28 \) electrons remaining. - Distribute these remaining 28 electrons around the fluorine atoms, ensuring each fluorine receives 8 electrons to complete its octet (bonding pair + lone pairs). 4. **Distribute Lone Pairs to Central Atom:** - After satisfying the octets of the fluorine atoms, any remaining electrons are placed on the central xenon atom. - Xenon can accommodate more than 8 electrons (expanded octet) because it is in Period 5 of the periodic table. ### Diagram Tools - There is an interactive canvas on the right with tools for drawing: - **Bond Tool (single bond):** Used to draw bonds between atoms. - **Lone Pair Electron Tool:** Used for adding lone pairs to atoms. - **Erase Tool:** For correcting mistakes. - **Undo Button:** To revert the last action. - **Help Button (? symbol):** Access help documentation. These tools will aid in accurately representing the Lewis structure of XeF
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