Draw approx. solution for the directional field for the first order with the initial condition y(0) = -1.8

Calculate the first derivative of a general cubic Bezier curve .We have a Bezier curve C1, that is described from the control points P0(0,0) , P1(3,3,),P2(6,3), and P3(8,1), and curve C2 that is described from the control point P4,P5,P6(11,5) and P7(15,9). Draw the curve C1 approximately and a control polygon

Compute the gradients of each of the following functions: o = xyz & = ln [(x² - y²)-¹/2] r = || = √√√x² + y² + x² 1/r Note: Remember that your tutorial has Hints in it, at the end of each chapter. If you're stuck, they are often quite useful! • If the answer is a scalar, you can just type it in the box (using the Calcpad if you like, or using / for fractions, ^ for exponents, shift and - for subscripts, etc.) For multiplication, you can either leave a space, or use *. So x*x=xx= x², Note that this is not the same as xx without a space; that will get read as an entirely different variable! • If you need to enter a vector, enter an ordered list of components, so for A you can enter either A = (A₂, Ay, A₂) = {A₂, Ay, A₂}. Note that the system isn't great with multiplying through by overall factors, so it's better not to write e.g. Vo= V = Vr = V= (2A, 2A, 2A₂).