Draw an alkyl halide that would undergo an SN2 reaction to yield this product under the conditions shown below. Use wedge and dash bonds to indicate stereochemistry where appropriate. Draw Starting Alkyl Halide CH3OK THE

Draw the major product of this reaction. Ignore inorganic byproducts. H3O*

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A bacteria produces an aromatic product starting with the enolate shown below.Step 1. An aldol condensation reaction.Step 2. Two keto-enol tautomerizations.Step 3. Ester hydrolysis followed by decarboxylation.  Draw the structure of the final product with formula C11H16O2

Complete these SN2 reactions, showing the configuration of each product.

Which best explains the following reaction. OH OH H3O+ This reaction does not work because the major product would be an alkene formed by elimination. This reaction does not work because the major product would be an ester. This reaction does not work because three ethers can be formed. This reaction works and the only ether product formed is shown. +

Show how the Wittig reaction might be used to prepare the following alkene. Draw the alkyl bromide and the carbonyl compound that you would use. H3C CH, • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • Do not include lone pairs in your answer. They will not be considered in the grading. • In cases where there is more than one answer, just give one. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate multiple reactants using the + sign from the drop-down menu.

Draw one product of an elimination reaction between the molecules below. Note: There may be several correct answers. You only need to draw one of them. You do not need to draw any of the side products of the reaction. o* o Br SH Ö + X Click and drag to start drawing a structure.

Q4. Alkyl halides are good at doing substitution (SN2/SN1) and elimination (E1/E2) reactions because the halide (X-) is a good LG. Alcohols on the other hand are not suitable for these reactions since hydroxide (¯OH) is a poor LG. However, an OH can be converted into a OTs (tosyl group) by reacting an alcohol with TsCl in presence of a base. An OTs is a good LG, and this allows us to indirectly (via OTs) use alcohols in substitution (SN2/SN1) and elimination (E1/E2) reactions. (4) OH TsCl NEt3 OTS Tosyl ester NaCN DMSO + HNEt3 Determine the major/minor products CH3OH heat OTS Tosyl ester TsCl = NaOCH3 CH3OH DBU Ś=0 CI

I need help drawing the product of this reaction. The starting material is vanillin and it is being treated with SO3 & H2SO4 in order to generate a product with the formula C8H8SO6.