Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Draw a logic Diagram that use only two-input NAND gates to implement the following expression
(XY+ X’Y’)(WZ’+W’Z)
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- Consider the following truth table. A 0 B001 В C Output 0 1 1 1 0 1 0 0 0 1 1 1 1 0 0 1 0 1 1 1 0 1 1 1 1 1a) 1b) Write the Boolean expression for the output using the sum-of-products (SOP) form. 1c) Draw the logic circuit using the expression derived in part (a). Use two-input gates (OR, AND) and single-input inverters. Write the Boolean expression for the output using product-of-sums (POS) form.arrow_forwardSimplify the given Boolean function and design its logic gates F3(x,y,z) = x’yz’+y’z+x’z’ F4(x,y,z) = x’y’+xz+x’z F5(x,y,z) = xy’z+x’y’zarrow_forwardDraw the combinational logic circuit diagram that implements F using NAND Gates only. F = a3’a1a0 + a2a1+ a3a2a0’+ a3a2’a1’a0arrow_forward
- The truth table for a Boolean expression is shown on figure1. A, B, C, D are inputs and Y is the output Write the Boolean expression on SOP form Y = f (A, B, C, D) Minimize the function using Karnaugh Map (K Map) Draw the minimized function using logic gatesarrow_forwardGiven the following logic circuit, a logic expression for the output function is: Z O F(x,y,z) = x.(z+y)+z.(z+y) OF(x,y,z) = (z+y).(x+z) O F(x,y,z) = x.z+x.y+z+z.y O F(x,y,z) = x.y+z O All of the above O None of the above Farrow_forwardboolean expression: P = not((not(a.b) + c) + a.c) (c) Show that P (the Boolean expression above) is equivalent to the Boolean expression Q = a · b · not(c) and draw the corresponding circuit.arrow_forward
- One way to think of logic gate types is to consider what input states guarantee a certain output state. For example, we could describe the function of an AND gate as “Any low input guarantees a low output.” Identify what type of gate is represented by the following phrase: “Any low input guarantees a high output.”arrow_forwardA Full Adder Circuit is shown in Figure 1 utilizing two Half Adders and an OR Gate. The major input bits are A and B, the carry input is CIN, and the Sum and Carry Outputs are COUT, respectively. simulate it using C programming Efficient logic, use of loops and conditional statements Truth table: (Half adder) A B Sum Pi=A⊕B Carry, Gi=AB 0 0 0 0 0 1 1 0 1 0 1 0 1 1 0 1 Truth table: (Full adder) A B Ci Sum, S=A⊕B⊕Ci Carry, C0=AB+CiA⊕B 0 0 0 0 0 0 0 1 1 0 0 1 0 1 0 0 1 1 0 1 1 0 0 1 0 1 0 1 0 1 1 1 0 0 1 1 1 1 1 1arrow_forwardDraw the truth tables for the following Boolean expressions. xy+yz+xz x¯y+yz¯+x¯z (x⊕y)+(y⊕z)+(x⊕z) (xy)¯⊕ z 2.Draw circuit diagrams implementing each of the above expressions. You may simplify the expressions or not, as you choose. You may use any of the six fundamental logic gates (AND, OR, NOT, NAND, NOR and XOR). I need help on question 2 containing the circuit diagramsarrow_forward
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