Dock diving is a great form of athletic competition for dogs of all shapes and sizes. Sheba, the American Pit Bull Terrier, runs and jumps off the dock with an initial speed of 8.82 m/s at an angle of 28°with respect to the surface of the water. (Assume that the +x axis is in the direction of the run and the +y axis is up.) (a) If Sheba begins at a height of 0.76 m above the surface of the water, through what horizontal distance does she travel before hitting the surface of the water? Answer In m please (b) Write an expression for the velocity of Sheba, in component form, the instant before she hits the water. (Express your answer in vector form.)  (c) Determine the peak height

Dock diving is a great form of athletic competition for dogs of all shapes and sizes. Sheba, the American Pit Bull Terrier, runs and jumps off the dock with an initial speed of 9.52 m/s at an angle of 28° with respect to the surface of the water. (Assume that the +x axis is in the direction of the run and the y axis is up.) (a) If Sheba begins at a height of 0.83 m above the surface of the water, through what horizontal distance does she travel before hitting the surface of the water? m (b) Write an expression for the velocity of Sheba, in component form, the instant before she hits the water. (Express your answer in vector form.) V = m/s (c) Determine the peak height above the water reached by Sheba during her jump. m Need Help? Read It

A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as functions of time are given by  x = 17.0t  and  y = 4.20t − 4.90t2,  where x and y are in meters and t is in seconds. (a) Write a vector expression for the ball's position as a function of time, using the unit vectors î and ĵ. (Give the answer in terms of t.) =          m By taking derivatives, do the following. (Give the answers in terms of t.) (b) obtain the expression for the velocity vector  as a function of time =          m/s(c) obtain the expression for the acceleration vector  as a function of time =          m/s2(d) Next use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the golf ball at t = 3.24 s.   =         m   =         m/s   =         m/s2

A golf ball is hit upward, with an initial velocity of 47 meters per second, at an angle of 25° with respect to the horizontal. The ball is hit from a height of 8 meters above the ground.   The horizontal distance x from the starting point and the height y above the ground of the ball t seconds after it is hit are given by the parametric equations below.   x=(v0cosθ)t y=−4.9t^2+(v0sinθ)t+h Here v0 is the initial velocity, θ is the initial angle with respect to the horizontal, and h is the initial height.   Use the equations to answer the following questions.   (a)How long is the ball in the air before it first touches the ground?Do not round any intermediate computations. Round your answer to the nearest hundredth. _____ seconds (b)What is the horizontal distance the ball travels before it first touches the ground?Round your answer to the nearest whole number. _____ meters