Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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1. Hemophilia is a sex-linked genetic disease caused by a recessive allele. If a woman who was a carrier
for hemophilia married a man who was healthy, what fraction of their children would be likely to have hemophilia?
A. 1/4
B. 1/2
C. 0% chance their children would get it
D. 3/4
2. In cats, black fur color is dominant over brown fur color. If a heterozygous black cat was crossed with
a brown cat, what fraction of the kittens would be black?
A. 50%
B. 25%
C. 75%
D. 0%
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- 4. In this pedigree of another family with hemophilia A. If the woman Il-2 has a son, what is the chance that he is affected? II B. If the woman Il-2 has a daughter, what is the chance 1 2 3 4 III that she is affected? -1 C. If the woman Il-2 has 2 sons, what is the chance that neither will be affected? D. What are the chances that the child of II-4 and Il-5 will be affected?arrow_forwardBelow is a pedigree for a family into which Individual III-4 has married. He and his spouse, Individual III-3, are visiting a genetic counselor because they are expecting a baby (Individual IV-1). They want to know the chance that the baby will get the autosomal recessive genetic disease seen in Individual II-2. Overall, in the population, the disease is known to affect 1 in 625 individuals in the population to which this family belongs [assume this frequency is the result of random mating so represents f(aa)] I. II. E III. IV. 1 1 2 2 3 1 3 1 4 2 4 5arrow_forward11. Determine the Chi Square value of a dihybrid test cross that follows Mendel's Laws of Inheritance and produced the following numbers: 31, 21; 19, and 29. A. 1.04 B.4.00 C. 4.16 D. 9.38 c. 2.00 F. none of the answers is correctarrow_forward
- A man is homozygous normal and his wife is heterozygous for a genetically inherited recessive decease. What is the probability that they will have a healthy child? Group of answer choices a. 2 out of 4 b. 1 out of 4 c. 3 out of 4 d. 4 out of 4arrow_forward1. A man and woman are both affected with the BRCA1 gene for familial breast cancer, a disease that has 80% penetrance in all individuals who carry the allele. They are both heterozygotes for the disease-causing mutation. What is the probability that they will have a phenotypically normal child?a. 20%b. 40%c. 60%d. 50%e. 80% 2. In populations in Hardy-Weinberg equilibrium, the heterozygote frequency is maximal when the A allele equalsa 0b 0.2c 0.5 d 0.8e 1.0arrow_forwardRed-green color blindness is controlled by a recessive allele on the X chromosome. A colorblind father and a normal vision mother have a daughter with red green color blindness. If they have a son what is the probability that he will be color blind? Group of answer choices a. 0.75 b. 0.5 c. 0 d. 1 e. 0.25arrow_forward
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