College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Discuss separately, how the angle of projection varies with Time, Range and Height for a fixed speed of a projectile.
Discuss separately, how the velocity of projection varies with Time, Range and Height for a fixed angle of a projectile.
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- 3. A cannon on Earth (located at the origin) launches a projectile, of mass m, horizontally at height y = 0 m with speed vo, as shown in the figure below: y (m) ↑ x (m) Fw There is a strong wind that imparts a force with constant magnitude Fw, in the negative x-direction, on the projectile as it is airborne. Voarrow_forwardConsider a projectile being launched with an initial speed of 43 m/s at a variety of initial angles. Refer to the figure. What is the range, in meters, of the projectile if it is launched at an angle of θ1 = 79.7°? What is the range, in meters, of the projectile if it is launched at an angle of θ2 = 40.5°? What is the range, in meters, of the projectile if it is launched at an angle of θ3 = 90 − 79.7°, the complement of θ1?arrow_forwardTwo carts have velocities vand v, respectively. At t = 0 the distance between the two carts were zero. A passenger in cart A wants to throw a ball to cart B. The ball's initial speed with respect to cart A is vo. (a) What angle should the projectile have to reach cart 2? (b) What will be the projectile's speed at maximum height with respect to cart A, cart B, and the ground respectively? A UA B VBarrow_forward
- A projectile is fired with initial speed 150 m/s and an angle of elevation 45° from a position 10 m above ground level. Where does the projectile hit the ground and with what speed? Solution If we place the origin at ground level, then the initial position of the projectile is (0, 10) and so we need to adjust the parametric equations of the trajectory by adding 10 to the expression for y. With v0 = 150 m/s, ? = 45°, and g = 9.8 m/s2, we have x = 150 cos ? 4 t = y = 10 + 150 sin ? 4 t − 1 2 (9.8)t2 = . Impact occurs when y = 0, that is 4.9t2 − 75 2 t − 10 = 0. Solving this quadratic equation (and using only the positive value of t), we get the following. (Round your answer to two decimal places.) t = 75 2 + 11,250 + 196 9.8 ≈ Then x ≈ 75 2 (21.74) ≈ (rounded to the nearest whole number), so the projectile hits the ground about…arrow_forwardLesson: Projectiles If two projectiles have the same size and shape but one is heavier than the other, which will travel further horizontally if they are both launched at the same angle and speed? O The heavy one O They will both be the same O The light one O Not enough information to tellarrow_forwardUse a graphing utility to obtain the path of a projectile launched from the ground (h = 0) at the specified values of θ = 35°, v0 = 300 feet per second. In the exercise, use the graph to determine the maximum height and the time at which the projectile reaches its maximum height. Also use the graph to determine the range of the projectile and the time it hits the ground. Round all answers to the nearest tenth.arrow_forward
- Anthony carelessly rolls his toy car off a 79.0-cm-high table. The car strikes the floor at a horizontal distance of 96.0 cm from the edge of the table. (a) What was the velocity with which the car left the table? (Enter the magnitude.)(b) What was the angle of the car's velocity with respect to the floor just before the impact?arrow_forwardA particle is projected with a velocity such that its range on the horizontal plane is twice the greatest height attained by it. The range of the projectile is (where g is acceleration due to gravity)arrow_forwardProjectile #1 is launched at t%=DOs at position (0,0) with an initial x-velocity of 5m/s and y-velocity of 10m/s. Projectile #2 is launched 1s after projectile #1 from an initlal position of (1,1) with an x-velocity of 10m/s. Find the following: The position that the 2 projectiles collide at, the time it takes to collide, and the Initial velocity of projectile #2 Including the launch angle.arrow_forward
- Question 2. A projectile is fired from the ground with an initial speed v at an angle 0 above the horizontal. (a) At t = 0, what is the velocity vector? (b) At what time t' does the projectile reach its maximum height? (c) What is the velocity vector at the top of the trajectory? (d) What is the horizontal distance traveled by the projectile? (e) At what angle should one launch the projectile to maximize horizontal distance traveled?arrow_forwardProjectile A is launched at an angle of 20 degrees to the horizontal with initial speed u. Projectile B is launched at an angle of 70 degrees to the horizontal, also with an initial speed u.(a) Compare the times of flight of the two projectiles.(b) Show that the ranges of both projectiles are equal.arrow_forwardA river of width' a'with straight parallel banks flows due north with speed u. The points O and A are on opposite banks and A is due east of O. Coordinate axes Ox and Oy are taken in the east and north directions respectively. A boat, whose speed is v relative to water, starts from O and crosses the river. If the boat is steered due east and u varies with x as : u = x(a – x)- Find : absolute velocity of boatman when he reaches the opposite bankarrow_forward
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