Differentiate: (x) = sin(x) – csc(x) A A j'(x) =cos(x) - cse(x)cot(x) ® j'(x) = - cos(x) – csc(x)cot(x) © i(x) =cos(x) + cse(x) cot(x) D j'(x)=- cos(x)+ csc(x)cot(x)

Q: Find f'(x) for f(x) = A f'(x) - B f'(x) = © f(x)= 2x+cos²x tanx 2-2sinxcosx tanx 2x+cos²x sin²x…

A: Given: The function fx=2x+cos2xtanx Find the derivative of the given function Formula used: The…

Q: determine the general derivatives f(x)= -3 f(x)= sin x + cos x -sec2x

A: Simple use the identity of derivative of constant is zero and derivative of sinx is cosx and…

Q: f'(x) = Let f(x)= = I cos ³

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Q: Find f'(x) if ƒ (x) = 6 cos x + 10 sin x. S'(x) =|

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Q: Find the critical point of the function f(x) = 3x² – 12x Answer:

A: We will find out all the required values.

Q: Let f(x) = 2 csc (7x) f'(x) = - -14 cot (7x) csc (7x) X

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Q: Let f(x) 4 cos x + 2 tan x f' (æ) = r(금)- f'

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Q: Let .f(x) = - 4 cos? x f'(x) =

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Q: f(x) = -2x cos(x)

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Q: If f(x) f'(x) = = COs x 4 tan x, then f'(4) = Check Answer

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Q: If f(x) = cos a- 5 tanx, then %3D f'(x) = %3D f'(5) =

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Q: Let f'(x) = f'( 5 ) = f(x) = 3 sin x + 12 cos x

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Q: Verify the equation

A: To establish the given trigonometric identity

Q: f(x)=x+sinx / x2+cosx f '(x)=?

A: Given function: Now,

Q: F(x)=2x sin(x)Tan(x) find f'(x)

A: Use the concept of derivative of the form  f = uvw

Q: Let f(x) = (7 sin x + 2 cos x)tan-lx f'(x) = %3D

A: topic - derivatives

Q: If f(x) f'(x) = COS x 3 tan x, then - f' (5) =

A: Derivative of cosx is -sinx.

Q: Find F'(x), f"(x) and f'"(x) for f(x)=x$+cos(9x).

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Q: CSCX -1 Differentlate: f(x) = secx A f'(x) = - csc2x+ sinx f(x) = sinx - sec²x C rx)=cosx-sec2x f(x)…

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Q: et f(x)=-11sin x+3 cos x f' (x)=?

A: f(x)=-11sin x+3 cos x this is given  we have to differentiate the function  dsinx/dx = cosx…

Q: LIf f(x) = 2 sin(x) + 2x* , find f' (3). f'(3) =

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Q: F CSC'x + - cos2x -cos^x -sec'x

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Q: If f(x) ƒ'(x) = f'(2) = 4 sin x 3 + cos x then

A: derivative

Q: f(x)=-7x(sin(x)+cos(x)) f’(pi/4)=?

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Q: Find f'(x) = = 4-5 sin(x) cos²(x) f(x) = -4 sin(x) + 5 cos(x)

A: Given : f(x)=-4sin(x)+5cos(x)   To Find : f'(x)

Q: Let f(x)=(6sinx+2cosx)tan−1x f'(x) =

A: Consider the function

Q: = If f(x) = f'(x) = ƒ'(5) = 4 tan x, then - sin(x)-4 sec² (x) Cos x

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Q: f(x) = 7 sinx+ 5 cos x

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