Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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Question
Differentiate the function.
 
f(x)=6x2−2x+14x2+3x−8
 
The derivative of
f(x)=6x2−2x+14x2+3x−8
is
Differentiate the function.
f(x) = (6x² - 2x + 1) (4x² + 3x -
Which of the following shows how to find the derivative of f(x)?
(x (
(6x² - 2x +1
+ 1) ) (4x² + 3x - 8) - (6x² - 2x + 1) [ (4x² + 3x-8))
dx
dx
OA. f'(x)=-
(4x²+3x-8
+3x-8) ²
d
○ B. l'(x)= (& (8x²-2x+1)] (6x²-2x+1) - (4x² + 3x −8) (ax (4x² + 3x −8))
+
dx
OC. f'(x) =
d
(6x² - 2x+1) (x (4x² + 3x-6)] - [ (x²-2x+1)) (4x² + 3x-6)
dx
dx
(6x² - 2x + 1)²
○d. Fox) = ( (8x²–2x+1)] (4x² + 3x −8) + (6x²³-2x + 1) ( (4x² + 3x-6))
O D. f'(x)=
dx
dx
The derivative of f(x) = (6x² − 2x + 1) (4x² + 3x-
-
+3x-8) is
expand button
Transcribed Image Text:Differentiate the function. f(x) = (6x² - 2x + 1) (4x² + 3x - Which of the following shows how to find the derivative of f(x)? (x ( (6x² - 2x +1 + 1) ) (4x² + 3x - 8) - (6x² - 2x + 1) [ (4x² + 3x-8)) dx dx OA. f'(x)=- (4x²+3x-8 +3x-8) ² d ○ B. l'(x)= (& (8x²-2x+1)] (6x²-2x+1) - (4x² + 3x −8) (ax (4x² + 3x −8)) + dx OC. f'(x) = d (6x² - 2x+1) (x (4x² + 3x-6)] - [ (x²-2x+1)) (4x² + 3x-6) dx dx (6x² - 2x + 1)² ○d. Fox) = ( (8x²–2x+1)] (4x² + 3x −8) + (6x²³-2x + 1) ( (4x² + 3x-6)) O D. f'(x)= dx dx The derivative of f(x) = (6x² − 2x + 1) (4x² + 3x- - +3x-8) is
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