diagram b) Construct the load diagram c) Provide the values at each change of Load points d) Provide the values at each point of Zero Shear e) Given that the section modulus of the beam is 3250 determine the allowable bending stress, while ignori V (kN) k 1.6 2.4 2 36 16 20

Q: Can you add the datum line in the illustration and make a bettter illustration based on solution

A: Given, Angle made by nozzle = 45o Horizontal distance = 15 to 20 m

Q: x; ]] a» a» dz || X2 a3 a a33

A: For calculation assume,

Q: 5. Find diameter y. All dimensions are in millimeters. 1 + 19.30 DIA 118.00 -३०

A: Tapered beam with larger diameter at AB = 19.3 mm  Length of beam ,L = 118 mm  Tapered angle = 3°…

Q: Compute Ix for the region shown. y 2 18 2-5--5- -2 -8 8. Dimensions in inches

A: The area is divided into the standard areas as shown below.

Q: Determine the ỹ coordinate. y b. = ky? a

A:

Q: Locate the centroid 10 mm 20 mm 10 mm 10 mm 20 mm 50 mm y

A:

Q: 6 in Gin Gin 9 in 3in

A: Schematic diagram of the given problem:

Q: y 500 50 80 -140- - 140- 80 60 400 500 50 500

A: Given- plate area is given  To find- centroid of given plate area

Q: X 0.75 3 -3.5 1.5 1.5

A:

Q: From the rectangular area shown a semi-circle of radius 4 cm is removed. Locate the centroid, (C),…

A:

Q: 4- Which statement is true about the precedence of lines? A. a hidden line has precedence over a…

A:

Q: According to this figure, What is d? What is dt?

A: Draw the figure.

Q: 05 Find the XT 0.5 1.5 3 2.5

A:

Q: * Dount command Creates a filled circle or a filled ring O a filled circle or a wide ring. a wide…

A:

Q: Find the domains of: f(x)=- x - 9 a. {x\x€R, x#9} b. {x|x€R, x#-3, x#3} c. {x|x€R, x+-3, x # 3, x #…

A: Hello dear this is the solution of your problem The answer is found to be Option (b)  For…

Q: a) top most, hef tmost

A: X = 1.5 cm Y = 5.48 cm

Q: 31⁄5 / 4⁄7

A: 31/5=6.2 4/7=0.571

Q: +y") dx ly

A:

Q: 80 38 24 340 R24 25 R40 130

A: It is not possible that every command and steps that is used in the drawing is to write down here…

Q: [Choose ] solve equilibrium equations simultaneously ensure you have an equal number of unknowns and…

A: Understand force flow. Understand the math behind structural analysis (concepts like virtual work…

Q: 38 O 18 22 66 102 The known: front projection, side projection Required: Draw the three projections…

A:

Q: How do I get the support forces

A: The x and y are the vertical and horizontal distances: x=12cos60=6 fty=6sin60=5.196 ft

Q: where did 3sqrt of 2 came from?

A: Given, A structure with carrying varying load   To find : Where 32 came from.

Q: Y

A:

Q: 4 cm 0 2 י 5 cm 4 567 Value: cm 10 5 150 Value: mm 0 140

A: There are two scales, and the values shown on the two scales are required.One is the main scale and…

Q: The block of mass m1 = m0 is attached to a spring of elastic constant k = (m0g)/H and natural length…

A:

Q: * .I don't like this," said Ali“ Correct Incorrect

A: The correct punctuation marks for this be like this "I don't like this," said Ali.

Q: A Derive the equation for the unit influence line for the reaction at the support B in the…

A: By Muller Breslau method, remove Reaction at support B and place a Load of P as shown in figure. By…

Q: 500 50 60 400 500 50 80 - 340 80

A:

Types of Composite

Composite materials are formed by merging two components that have different chemical and physical properties. The merged output is termed as a composite, whose properties are completely different from the individual components. Composite materials also have better strength than the individual components.Composite materials usually have two main parts, reinforcement material, and matrix material. The matrix material acts as a binder and surrounds the fiber of another material that bears a much higher strength. This material is known as the reinforcement material. The matrix materials are usually high-strength additives resins, while the fibers of the reinforced material can be random, oriented, and in a mat format.Composite materials are also known as fiber-reinforced composite polymers because they are composed of the polymer matrix which is reinforced to laboratory-created fibers or naturally occurring fibers, such as glass fibers, carbon fibers, or aramid fibers. Under the application of external loads, the matrix material absorbs and transfers the loads to the fibers, these fibers in return provide good compressive strength, tensile strength, and stiffness to the fiber-reinforced composite materials.Depending upon the matrix and the reinforcement material, different properties can be induced to the fiber-reinforced composite materials, including good corrosion resistance properties. The most common matrix material is the resin while the glass fibers act as the reinforcement material. Strong fibers provide strength and stiffness to the composite materials while, a soft and flexible resin provides shape to the composite materials.