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- O University of Tampa - Prod - My x Bb Assignments - Introductory Cher x 101 Chem101 b My Questions | bartleby Ô https://app.101edu.co Not syncing Question 2 of 10 Submit The average adult human burns 2.00 x 10° kcal per day in energy. What is this rate in kJ per hour ? STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 1 4184 349 1000 0.001 1.15 x 105 4.184 60 2.00 x 10° 2.01 x 10° 24 20.0 J cal kJ min kcal/day kcal hr 9:26 PM P Type here to search a A O G E D 4) 10 5/4/2021Ac₂0/NaOAc PhCO,H HNO,/H₂SO4 NowAktiv Chemistry → C < + X b Success Confirmation of QX M Your Chemistry answer is rex b Answered: How many mL o x b Answered: A student combi x app.101edu.co Time's Up! A 0.660 M solution of KCI needs to be prepared through dilution. A 2.00 M stock solution will be added to a 0.250 L volumetric flask and then water will be added to the 0.250 L mark. Determine the volume (in mL) of the 2.00 M stock solution of KCI needed to produce this solution. 1 4 7 +/- New Tab 2 5 8 mL 3 6 9 G 0 x + Submit X C x 100
- Without doing any calculations, match the following thermodynamic properties with their appropriate numerical sign for the following exothermic reaction. 2H2(g) + O2(g)–→2H20(g)Drug Concentration A pharmaceutical companyclaims that the concentration of a drug in a patient’sbloodstream will be at least 10% for 8 hours. Supposeclinical tests show that the concentration of a drug (aspercent) t hours after injection is given byC(t) = 200t/2t2 + 32During what time period is the concentration at least10%? Is the company’s claim supported by the evidence?Explanation is needed. Thank you! <33
- Electrodes Solutions Setup 1 Anode Zinc Zn(NO3)2 1.0 M Cathode Silver AgNO3(aq) 1.0 M % error = Setup 2 Anode Zinc Zn(NO3)2 1.0 M aA(aq) + bB(s) CC(aq) + dD(s) Cathode Anode Silver Zinc AgNO3(aq)| Zn(NO3)2 Concentrations Ecell, V 1.548 Compare the experimental Ecell values to the theoretical Ecell values by calculating percent error using Eqn 8b-4. experimental value - literature value literature value 1.536 0.50 M x 100 An electrode potential is a measure of the extent to which the concentrations of the species in a half cell differ from their equilibrium values. Consider the reversible half reaction: Setup 3 (Rxn 8b-4) 0.50 M Cathode Silver AgNO3(aq) 1.0 M 1.559 (Eqn 8b-4)Standardization of NaOH solution using KHP *MW of KHP = 204.22 g/mol Calculate for the concentration in Molarity (M) of NaOH supplied in the burette. MASS OF KHP (g) VOLUME OF KHP Solution (mL) 250 2.725 1 2 3 Using a pipette, 50 mL aliquot was taken from the prepared solution to titrate with NaOH. TRIAL V Analyte (mL) Final Reading of the Titrant (mL) 25.1 25.3 25.2 50 50 50 Initial Reading of the Titrant (mL) 50 50 MOLARITY KHP Solution (M) 3 50 AVERAGE Volume of Titrant used (mL) 1 1 1 MOLARITY NaOH (M) 4 4 4 232x882 2715028=62±3272 Rb K Ba Ca Na Mg AI Mn Zn Cr Co Sn H₂ Cu Ag Hg Reference: Activity Series react with cold water and acids, replacing hydrogen react with acids or steam, but usually not liquid water, to replace hydrogen react with acids, but not water, to replace hydrogen ***reference point*** react with O to form oxides mostly unreactive Increasing Reactivity