Related questions
Question
Transcribed Image Text:=903 <980!
A coaxial cable has inner radius u, outer radius w (w>u), and length d.
Between the inner and outer conductors is a dielectric medium with a dielectric constant
of . A charge quantity of Q is uniformly distributed on the inner conductor surface. A
charge quantity of -Q is uniformly distributed on the inner surface of the outer conductor.
The whole coaxial cable is neutral.
A. Calculate electric field intensity between the inner and the outer conductors.
B. Find the voltage between the two conductors.
C. Find the capacitance of this coaxial cable.
Transcribed Image Text:Q₂
D-ds=Q, D = EE
V₁₂ = S³E-di, c=
√ dx = lnx
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution
Trending nowThis is a popular solution!
Step by stepSolved in 2 steps with 1 images
Knowledge Booster
Similar questions
- A. What is the capacitance (in µF) of a parallel plate capacitor having plates of area 1.25 m2 that are separated by 0.0230 mm of neoprene rubber? B.What charge (in µC) does it hold when 9.00 V is applied to it?arrow_forwardTwo 1.70-cm-diameter disks spaced 2.00 mm apart form a parallel-plate capacitor. The electric field between the disks is 4.80×105 V/m. You may want to review (Pages 699-702). For help with math skills, you may want to review: Area Calculations for a Circle Mathematical Expressions Involving Squares Part A What is the voltage across the capacitor? Express your answer to two significant figures and include the appropriate units. V = Submit Part B V = HÅ Value Request Answer Submit An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.40x107 m/s. What was the electron's speed as it left the negative plate? Express your answer to two significant figures and include the appropriate units. μA Value Units Request Answer Units By ? ?arrow_forwardA 3.0-cm-diameter metal ball has a surface charge density of 10 μC/m². ▼ Part A How much work is required to remove one electron from this ball? Express your answer with the appropriate units. W = Submit 1º- μÅ Value Request Answer Units ?arrow_forward
- Question is attached.arrow_forwardAarrow_forwardAn insulating rod of length L has a charge -q uniformly distributed along its length as shown in the figure. a) What is the linear charge density of the rod? b) Determine the electric field at point P located at a distance a from its end. c) If P were much further from the bar than L, it would appear to be a point load. Show that your answer b) reduces to the electric field of a Point charge a >> Larrow_forward
- How is charging by induction different than charging by conduction? Select one: O Charging by induction usually involves more than one step. O Charging by induction always ends up with two negatively charged objects. O Charging by induction always ends up with two positively charged objects. O Charging by induction can only involve conductors.arrow_forward1. The main difference between an insulator and conductor is that:a. an insulator cannot obtain a net electric chargeb. an insulator will not allow charges to flow freelyc. a conductor will obtain only net negative chargesd. a conductor will not emit an electric fielde. a conductor will not allow charges to flow freelyarrow_forwardT or F? a. For a parallel plate capacitor, the capacitance depends on the area of the plates and on the separation distance between the plates, it does not depend on the material the plates are made of. b. If a conductor is placed in an electric field, and is in electrostatic equilibrium, the electric field lines just inside the conductor will be parallel to its surface.arrow_forward
- A parallel-plate capacitor is formed from two 2.8 cm-diameter electrodes spaced 2.6 mm apart. The electric field strength inside the capacitor is 3.0 x 10° N/C. Part A What is the magnitude of the charge (in nC) on each electrode? Express your answer in nanocoulombs. Πνα ΑΣφ ? Q = nCarrow_forwarda. Calculate the potential difference Vo - Va due to the infinite rod of uniform charge density X, as shown below. Perform this calculation by directly integrating the electric field over a path between a and b. I need to show all works step by step like physics and matharrow_forwardPart A The voltage across a 4 μF capacitor increases by 48 V. If the final charge on the capacitor is 507 μC, determine the initial charge. Q₁ = Part B Two parallel plates each have a charge magnitude of 601 nC. Between the plates is a dielectric with K = 86. Additionally, the E-field between the plates is 7.81x105 V/m. Determine the area of each plate. A= Part C A capacitor with no dielectric has an E-field of 88 kV/mm between the plates. The area of each plate is 46.3 cm² and the voltage across the capacitor is 1.5 V. Determine the capacitance. C=arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios