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device can fail in four different ways with probabilities t = 0.2, n, = 0.1, n3 = 0.4, and 14 3. Suppose there are 12 devices that fail independently of one another. What is the robability of 3 failures of the first kind, 4 of the second, 3 of the third, and 2 of the fourth?

device can fail in four different ways with probabilities t = 0.2, n, = 0.1, n3 = 0.4, and 14 3. Suppose there are 12 devices that fail independently of one another. What is the robability of 3 failures of the first kind, 4 of the second, 3 of the third, and 2 of the fourth?

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter12: Probability
Section12.3: Conditional Probability; Independent Events; Bayes' Theorem
Problem 42E
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Problem 6 A device can fail in four different ways with probabilities a = 0.2, 1, = 0.1, n3 = 0.4, and t4 = 0.3. Suppose there are 12 devices that fail independently of one another. What is the probability of 3 failures of the first kind, 4 of the second, 3 of the third, and 2 of the fourth?
Transcribed Image Text:Problem 6 A device can fail in four different ways with probabilities a = 0.2, 1, = 0.1, n3 = 0.4, and t4 = 0.3. Suppose there are 12 devices that fail independently of one another. What is the probability of 3 failures of the first kind, 4 of the second, 3 of the third, and 2 of the fourth?
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