Develop the Huffman code tree for the following character set and generate the compressed form of "abracadabra". Lower frequencies should be the left child of newly created nodes (similar to the pseudo code in the textbook). {"a" 0.15, "b" = 0.25, "c" = 0.1, "d" = 0.3, "r"=0.2} 1101101100011
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- I have an assignment that requires me to read strings from a text file and insert them into a binary search tree. I am having a hard time reading the data from the file and passing it through a function. This is the code I have right now: struct tree_node {char *data;tree_node *left;tree_node *right;}; char **Read();tree_node *create_node(char **val); int main(){tree_node *root= NULL, *temp_node;char **val = (char**)malloc(sizeof(char*)*17);for (int i = 0; i < 17; i++) {val[i] = (char*)malloc(sizeof(char)*strlen(*val));}temp_node = create_node(val);root = insert(root, temp_node);printf("In Order: ");inorder(root);printf("\n");return 0;} char **Read() {int size;FILE *fp = fopen("in.txt", "r");fscanf(fp, "%d", &size);char** value = (char**)malloc(sizeof(char*));for(int i = 0; i < size; i++) {fscanf(fp, "%s", &value[i]);} fclose(fp);return value;} tree_node *create_node(char **val) {tree_node* temp = (tree_node*)malloc(sizeof(tree_node));for(int i = 0; i < 17; i++)for(int…Implement a __setitem__ function that also supports negative indices. For example: W = L2(Node(10, Node(20, Node(30))))print W[ 10, 20, 30 ] W[1]=25print W[ 10, 25, 30 ] W[-1]=35print W[ 10, 25, 35 ] Complete the code: def L2(*args,**kwargs): class L2_class(L): def __getitem__(self, idx): <... YOUR CODE HERE ...> def __setitem__(self, idx, value): <... YOUR CODE HERE ...> return L2_class(*args,**kwargs) W = L2(Node(10, Node(20, Node(30))))print(W)W[1]=25print(W)W[-1]=35print(W)The program written for binary search, calculates the midpoint of the span as mid: (Low + High)/2. The program works well if the number of elements in the list is small (about 32,000) but it behaves abnormally when the number of elements is large. This can be avoided by performing the calculation as: =
- Write a c++ code of link list which is used to take your data like name, mob, age , marks. After that you will display the data in Disp() function. Your code will be able to take 5 students data and also check which student marks is greater than from other. At the end you will delete any node from link list Please should create grading_fun(); Bonus > 80 A 70 B 60 C 50 DModify the given code to accept float instead of int as a coefficient in C LANGUAGE: // Node structure containing power and coefficient of// variablestruct Node {int coeff;int pow;struct Node* next;}; // Function to create new nodevoid create_node(int x, int y, struct Node** temp){struct Node *r, *z;z = *temp;if (z == NULL) {r = (struct Node*)malloc(sizeof(struct Node));r->coeff = x;r->pow = y;*temp = r;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}else {r->coeff = x;r->pow = y;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}} // Function Adding two polynomial numbersvoid polyadd(struct Node* poly1, struct Node* poly2,struct Node* poly){while (poly1->next && poly2->next) {// If power of 1st polynomial is greater then 2nd,// then store 1st as it is and move its pointerif (poly1->pow > poly2->pow) {poly->pow = poly1->pow;poly->coeff = poly1->coeff;poly1 =…def strPattern(mystr):lenght = len(mystr)mystr1 = ""for i in range(lenght - 1):mystr1 = mystr1 + mystr[i].upper() + str(i + 1)if lenght == 0:return mystr1return mystr1 + mystr[-1].upper()s = input("enter a word: ")print(strPattern(s)) s = input("enter a word: ") EOFError: EOF when reading a line HOW CAN I FIX THIS QUESTION?
- By using Java, Give implementation of binary search tree (BST) using array, that displays the following menu:1. Read a list of values to be inserted in a new BST (if exist ignore the old BST)2. Display the content of the BST in preorder3. Display the content of the BST in inorder4. Insert a new element5. Delete an element6. Search an element7. Check if BST is complete8. ExitComplete this C++ Program by: Making all the nodes connect to each other (Make them as a list) Assign values to the data tiems of the 3rd node (stud3) * Display the data items of all nodes but have to use * stud1 as reference. CODE IS ON THE PHOTO.Write a function called PtrToSuccessor that finds a node with the smallest key value in a tree, unlinks it from the tree, and returns a pointer to the unlinked node. **Please Do Not Use Any Pre-Implemented Code, And It Is Not A Binary Search Tree*l **I NEED C++ CODE, NOT C CODE** Thank you.
- Write a for loop to print all NUM_VALS elements of vector courseGrades, following each with a space (including the last). Print forwards, then backwards. End with newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.size() - 1 (Notes)C++ without using std:: Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element vector (vector<int> courseGrades(4)). See "How to Use zyBooks".Also note: If the submitted code has errors, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>#include <vector>using namespace std; int main() { const int NUM_VALS = 4; vector<int> courseGrades(NUM_VALS); int i; for (i = 0; i < courseGrades.size(); ++i) { cin >>…Urgent! It's just a question and explained in detail.I need expert help on this question. I can't solve the question and I keep making mistakes.C language, tree and list structure will be used. The aim is to save the words in a given text file (.txt) in the tree structure given below and speed up the search. After parsing each word in the text file, both the word itself and the line number of the words in the text will be recorded in the tree.Below is an example of what to do.It will be accepted that the following sentence is in the first line of the text. This is the first sentence of the text and you can write whatever you want in the (.txt) file, my dear experts.“There are cups in a bin with binary bits on them kept in a cupboard" The nodes of the tree are indicated by circles. Each node contains a character and a reference to a link list. Whether there is an element in the link list depends on whether that node is the last letter of a word in the text. More explanations are…Modify the given code in C Language to act as given in the example: MyCommand: hello world MyCommand: print result > hello worl d so if the string is longer than 5 characters it will save the first 5 characters will be stored in a node and the rest of the string will be stored in another node. Please modify the given code .. I don't want a new code. The code: #include<stdio.h>#include<stdlib.h>#include<string.h> struct node{char data[100];struct node* next;}; int elements = 0;// function for add values to stackstruct node* add(struct node* stack, char *str){struct node* tp = (struct node*)malloc(sizeof(struct node)) ;strcpy(tp->data,str);tp->next = stack;elements++;return tp;}//redo functionvoid redo(){elements++;}//undo functionvoid undo(){elements--;} //print functionint print(struct node* stack,int idx){if(stack == NULL)return 0;idx = print(stack->next,idx);if(idx<elements)printf("%s\n",stack->data);return idx+1;} //function for save in…