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Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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I need answers for questions 31 and 32. I need solutions step by step.

Transcribed Image Text:* Reviews ar
M Passport
+ Lab 08 -G X
O UNFCU D
* Exam #2:
CO answer_1.p X
b bartbleyba x
b My Questi
F file_18.pdf x
+
O File | C:/Users/Arash%20Shakib/Downloads/Documents/file_18.pdf
n=2 1 in n
n=1
n=1
Determine whether the series converges or diverges. Justify your answers.
2+(-1)"
* 1+n+n²
31.
32.
= nyn
=l V1+n² +n°
Complete parts (a) through (c) for problems 33 and 34.
(a) Approximate the sum using 5 terms.
(b) Find the maximum error of the approximation and write the upper and lower bounds for the sum.
(c) Find the number
terms required to approximate the sum with an error less that 0.0001.
n
34. É-
'n +1
33.
5:27 AM
P Type here to search
98%
93°F Sunny
Hi
11/13/2021
Expert Solution
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- please give me a step by step solution for the following problem: 6(-9)-(-8)-(-7)(4)+11arrow_forwardTwo students, James and Joe were solving the equation 6-5(11-2x) = 17x. Their work is shown below for questions 2 - 5. James' Work 6-5(11-2x) = 18x 6-5(11-2x) =18x 6 6 -5(11-2x) = 3x -55 + 10x = 3x -10x10x -55 = -7x -7 -7 7 = = x J:SC Joe's Work 6-5(11-2x) = 17x 6-55 +10x = 17x -49 + 10x = 17x -10x10x : -49 = -7x -7 -7 7=x first stop the students used in solving the equation.arrow_forward
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