Determine the vertex, focus, directrix, and axis of symmetry of the parabola with the given equation. Sketch the graph, and include these points and lines. 1. y² 2.5x2 = 100y 3. y² + 4x14y = -53 4. y² - 2x + 2y - 1 = 0 5. 2x² 12x + 28y = 38 = -36x -

Write the equation of the parabola that opens up, has a vertex V(3,-3), and is congruent to y = ². Answer in the form y = a(x - h)² + k. Oy=(x+3)² +3 Oy=(x+3)²-3 y=(x+3)²-3 Oy=(x-3)2-3

H 8) Given 3y² +18y-10x=13, find the vertex, focus and directrix and graph it. Find the x & y intercepts and plot them to help you graph the parabola accurately. y -9 ++ -8- -7- -6- -5- -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 -1- -2- -3- -4- -5- -6- -7- -8- 1 2 3 4 5 X 6 7 8 9 10

Determine the vertex of the parabola.y = -2(x - 5)2 + 2