Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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- Click and drag the steps in the correct order to show that if n is a positive integer, then n is even if and only if 7n +4 is even. Suppose that n is even. Suppose that n is not even. Thus, 7n + 4 = 14k +10= 2(7k+5). Then, 7n + 4 = 14k + 2 = 2(7k + 1). Since n is even, it can be written as 2k for some integer k. This is 2 times an integer; so it is even as desired. Then, n can be written as 2k +1 for some integer k. Thus, 7n + 4 = 14k +11 = 2(7k+5)+1. Then, 7n + 4 = 14k + 4 = 2(7k+ 2). This is 1 more than 2 times an integer, so it is odd. Resetarrow_forwardDiscrete Matharrow_forward
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