Determine the second electron affinity of O.

The elements in the periodic table are grouped by similar chemical properties, which come from the similarities in the arrangement of their electrons. These electron arrangements can be expressed as generic outer electron configurations, i.e., the electron configuration outside the noble gas core, for all periods in a group using n instead of a specific number. Similarly, the generic Lewis dot structures for each group can be drawn using X to represent a generic element symbol. Match each generic electron arrangement to the appropriate periodic group number. Note that not all of the electron arrangements must be used. 1A (1) X. ns² (n − 1) d¹ - ns² (n − 1) dª ns²np³ 2A (2) •X• ns³ ns2 3A (13) .x. ns² (n − 1) d² ns² (n − 1) d³ - 4A (14) Answer Bank ns² np6 5A (15) ns² np³ X ns²np ns²np¹ 6A (16) ns¹ ns² np² 7A (17) X ns² (n − 1) dº - ns² (n − 1) dº 8A (18)

Write equations corresponding to the following. a.) the fourth ionization energy of Te b.) the electron affinity of C- c.) the electron affinity of V3+ d.) the first ionization energy of Ba

A new element, element Jn, is discovered on a separate planet. The energy requires to ionize one mole of Jn atoms is about 4750 kJ/mol. What is the frequency of light necessary to ionize one atom of this element? 6. What is the frequency of a light source that has a wavelength of 620 nm? What is the energy this wave? of