Determine the required total passing sight distance for the following
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- If the time of initial maneuver is (5 sec.), the time of passing vehicle occupies the left lane is (11 sec ), average acceleration is (3.5 km/hr/sec.) ,speed of passing vehicle is (80km/hr) and the speed of the slow vehicle ahead is (45 km/hr), Calculate the Minimum Passing Sight distance (P.S.D.). * P.S.D. = 453.68 m O P.S.D. = 436.43 m P.S.D. = 563.12 m O P.S.D. = 542.44 m %3D P.S.D. = 425.25 m %3DA vehicle moving in wet weather along down grade highway of (- 4%) grade. The design speed (48mile/hr.), (f = 0.30), (t = 2.50 Sec.). The stopping sight distance you recommended is equal to: 471.784 ft. 480.424 ft. O 401.424 m/sec. O 345.434 ft. O 417.424 m.If the time of initial maneuver is (5 sec.), the time of passing vehicle occupies the left lane is (11 sec ), average acceleration is (3.5 km/hr/sec.) ,speed of passing vehicle is (80km/hr) and the speed of the slow vehicle ahead is (45 km/hr), Calculate the Minimum Passing Sight distance (P.S.D.). * P.S.D. = 436.43 m %3D P.S.D. = 563.12 m P.S.D. = 425.25 m P.S.D. = 542.44 m P.S.D. = 453.68 m This is a required question
- The following are specifications for traffic design of a highway:Speed of the passing car = 100 kphSpeed of the overtaken vehicle = 80 kphTime of initial maneuvers = 5 secTime passing vehicle occupies left lane = 10 secsDistance between the passing car and opposing car at the end of maneuver = 20 mAverage acceleration = 2.5 kph/sec. 1. Determine the required total passing sight distance for said road a. 502.75 m b. 602.75 m c. 702.75 m d. 402.75 m 1. Find the minimum required passing sight distance. a. 280.37 m b. 390.37 m c. 48.37 m d. 490.37 mCompute the minimum passing sight distance for the following data: Speed of the passing car = 96 kphSpeed of the overtaken vehicle = 80 kphTime of initial maneuver = 4 secsAverage acceleration = 2.4 kph/secTime passing vehicle occupies the left lane = 9 secsTime the passing vehicle meets the vehicle originally occupying the left lane = 6 secCompute the minimum passing sight distance for the following data: Speed of the passing car = 90kph Speed of the overtaken vehicle = 80kph Time of initial maneuver = 4 sec Average acceleration = 2.4 m/sec2 Time the passing vehicle occupies the left lane = 9sec Distance between the passing vehicle at end of its maneuver and the opposing vehicle = 80m
- Compute the minimum passing sight distance for the following data: Speed of the passing car=90kph, Speed of the overtaken vehicle=80kph, Time of initial maneuver=4sec, Average acceleration=2.4kph/sec, Time passing the vehicle occupies the left lane=9sec, Distance between the vehicle at the end of its maneuver and the opposing vehicle=80mCompute the passing sight distance for a road section with the following conditions time for initial maneuver of 5 sec average acceleration rate of 2.6 km/hr/sec time in which the passing vehicle travels over left lane is 10 sec average of passing vehicle speed is 70 kph19-5. Develop a signal timing for the intersection shown below. 30 ft N PHF = 0.92 Level terrain Target v/c ratio = 0.95 Moderate pedestrian activity Average approach speeds: 30 mi/h N-S 40 mi/h E-W 85 ft Crosswalk widths = 10 ft Crosswalk setback = 2.0 ft Vehicle deceleration (a) = 10.0 ft/s? Driver reaction time (t) = 1.0 s Pedestrian walking speed 3.5 s Length of typical vehicle = 18 ft l = e = 2.0 s Demand Volumes for Problem 16-4 O (veh/h) Аpproach Left Through Right ЕВ 200 800 120 WB 160 1,050 100 NB 10 420 10 SB 12 400 8
- Compute the intermediate sight distance for a freeway with a design speed of 80kph if the perception time is assumed to be 2.5 seconds with a skid resistance of 0.70. Assume brake efficiency to be 60%.The speeds of overtaking and overtaken vehicles are 90 km/hr. and 70 km/hr. respectively on a two-way traffic road. The acceleration of overtaking vehicle is 4.5 km/hr./sec. and reaction time is 2 seconds. Calculate Safe OSD and Minimum length of overtaking zone?Compute the minimum passing sight distance forthe following data. Speed of passing car – 90kph Speed of overtaken vehicle – 80 kph Time of initial maneuver – 4 sec Ave. acceleration – 2.4 kph/sec2 Time passing vehicle occupies left lane – 9 sec Distance between passing vehicle at the end of its maneuver and opposing vehicle – 80 m