Determine the pH of a solution that is 0.15 M CH3COOH and 0.10 M CH3COONa.

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Problem Statement:**

Determine the pH of a solution that is 0.15 M CH₃COOH and 0.10 M CH₃COONa.

**Solution Explanation:**

This problem involves a buffer solution composed of acetic acid (CH₃COOH) and its salt, sodium acetate (CH₃COONa). To solve this, the Henderson-Hasselbalch equation can be utilized:

\[ \text{pH} = \text{pK}_a + \log \left(\frac{[\text{A}^-]}{[\text{HA}]}\right) \]

Where:
- \([\text{A}^-]\) is the concentration of the acetate ion (\(CH₃COO^-\)).
- \([\text{HA}]\) is the concentration of acetic acid (\(CH₃COOH\)).
- \(\text{pK}_a\) is the negative logarithm of the acid dissociation constant (\(K_a\)) of acetic acid.

The values required for this calculation (e.g., \(K_a\) for acetic acid) would need to be looked up in a reference source.

Graphs or diagrams are not present in this image.
Transcribed Image Text:**Problem Statement:** Determine the pH of a solution that is 0.15 M CH₃COOH and 0.10 M CH₃COONa. **Solution Explanation:** This problem involves a buffer solution composed of acetic acid (CH₃COOH) and its salt, sodium acetate (CH₃COONa). To solve this, the Henderson-Hasselbalch equation can be utilized: \[ \text{pH} = \text{pK}_a + \log \left(\frac{[\text{A}^-]}{[\text{HA}]}\right) \] Where: - \([\text{A}^-]\) is the concentration of the acetate ion (\(CH₃COO^-\)). - \([\text{HA}]\) is the concentration of acetic acid (\(CH₃COOH\)). - \(\text{pK}_a\) is the negative logarithm of the acid dissociation constant (\(K_a\)) of acetic acid. The values required for this calculation (e.g., \(K_a\) for acetic acid) would need to be looked up in a reference source. Graphs or diagrams are not present in this image.
Expert Solution
Step 1

Given that

  Ka for CH3COOH = 1.8 × 10–5

Concentration  of CH3COOH = 0.15 M

Concentration of CH3COO = 0.10 M

The solution contains weak acid CH3COOH and its conjugate base CH3COO.

So, this is a buffer solution.

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