Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Using the blue bars as fillable selections in the ICE/RICE Table, calculate pH and Ka. (I know pH comes out to be 8.53 using the Henderson Hasselbalch equation, but the problem requires the ICE/RICE table to be filled, and I'm unsure how to approach it).

ol Verizon LTE
11:24
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Question 10 of 11
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Determine the pH of a buffer that is 0.95 M HBRO and
0.68 M KBRO. The value of pka for HBRO is 8.68.
1
2
3
Based on the given values, set up ICE table in order to
determine the unknown.
HBRO(aq) +
H2O(1)
= H;O*(aq) + BrO (aq)
Initial (M)
Change (M)
Equilibrium
(M)
5 RESET
0.95
0.68
8.68
+x
-X
+2x
-2x
0.95 + x
0.95 - x
0.95 + 2x
0.95 - 2x
0.68 + x
0.68 - x
0.68 + 2x
0.68 - 2x
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Transcribed Image Text:ol Verizon LTE 11:24 9 69% Question 10 of 11 Submit Determine the pH of a buffer that is 0.95 M HBRO and 0.68 M KBRO. The value of pka for HBRO is 8.68. 1 2 3 Based on the given values, set up ICE table in order to determine the unknown. HBRO(aq) + H2O(1) = H;O*(aq) + BrO (aq) Initial (M) Change (M) Equilibrium (M) 5 RESET 0.95 0.68 8.68 +x -X +2x -2x 0.95 + x 0.95 - x 0.95 + 2x 0.95 - 2x 0.68 + x 0.68 - x 0.68 + 2x 0.68 - 2x
ul Verizon LTE
11:24
9 69%
Question 10 of 11
Submit
Determine the pH of a buffer that is 0.95 M HBRO and
0.68 M KBRO. The value of pka for HBRO is 8.68.
1
Based on your ICE table and definition of Ka, set up the
expression for Ka in order to determine the unknown.
Do not combine or simplify terms.
Ка
Ka =
5 RESET
[0]
[0.95]
[0.68]
[8.68]
[x]
[2x]
[2x]?
[0.95 + x]
[0.95 - x]
[0.95 + 2x]
[0.95 - 2x]
[0.68 + x]
[0.68 - x]
[0.68 + 2x]
[0.68 - 2x]
8.68
0.939
4.79 x 10-6
2.09 x 10-9
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Transcribed Image Text:ul Verizon LTE 11:24 9 69% Question 10 of 11 Submit Determine the pH of a buffer that is 0.95 M HBRO and 0.68 M KBRO. The value of pka for HBRO is 8.68. 1 Based on your ICE table and definition of Ka, set up the expression for Ka in order to determine the unknown. Do not combine or simplify terms. Ка Ka = 5 RESET [0] [0.95] [0.68] [8.68] [x] [2x] [2x]? [0.95 + x] [0.95 - x] [0.95 + 2x] [0.95 - 2x] [0.68 + x] [0.68 - x] [0.68 + 2x] [0.68 - 2x] 8.68 0.939 4.79 x 10-6 2.09 x 10-9
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