Determine the pH of a buffer formed by dissolving 20.0 g NaCH:COO into a 500.0 mL solution of 0.150 M of CH:COOH. Assume the volume of the solution does not change. The value of Ka for CH:COOH is 1.8 × 10-5. ( PREV 1 2 3 NEXT > Based on your ICE table and definition of Ka, set up the expression for Ka in order to determine the unknown. Do not combine or simplify terms. Ка 1.8 x 10-5 %3D %3D

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**Problem Statement:**

Determine the pH of a buffer formed by dissolving 20.0 g of NaCH₃COO into a 500.0 mL solution of 0.150 M of CH₃COOH. Assume the volume of the solution does not change. The value of Kₐ for CH₃COOH is 1.8 × 10⁻⁵.

**Instructions:**

1. Use the ICE (Initial, Change, Equilibrium) table and the definition of Kₐ to set up the expression.
2. Do not combine or simplify terms.

**Expression for Kₐ:**

\[ K_a = \frac{\text{[H⁺][A⁻]}}{\text{[HA]}} = 1.8 \times 10^{-5} \]

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Transcribed Image Text:**Problem Statement:** Determine the pH of a buffer formed by dissolving 20.0 g of NaCH₃COO into a 500.0 mL solution of 0.150 M of CH₃COOH. Assume the volume of the solution does not change. The value of Kₐ for CH₃COOH is 1.8 × 10⁻⁵. **Instructions:** 1. Use the ICE (Initial, Change, Equilibrium) table and the definition of Kₐ to set up the expression. 2. Do not combine or simplify terms. **Expression for Kₐ:** \[ K_a = \frac{\text{[H⁺][A⁻]}}{\text{[HA]}} = 1.8 \times 10^{-5} \] **Navigation:** - PREV (1) - CURRENT (2) - NEXT (3)
**Instruction:**

**Determine the pH of a buffer formed by dissolving 20.0 g NaCH₃COO into a 500.0 mL solution of 0.150 M of CH₃COOH. Assume the volume of the solution does not change. The value of Ka for CH₃COOH is 1.8 × 10⁻⁵.**

**Buffer Preparation Steps:**

1. **Calculate Molarity of NaCH₃COO:**
   - Dissolve 20.0 g NaCH₃COO in a 500.0 mL solution.
   - Determine moles and convert to molarity.

2. **Use ICE Table to calculate equilibrium concentrations:**
   - **Initial Concentrations (M):**
     - CH₃COOH(aq): [Initial]
     - H₂O(l): [Pure Liquid, not included in equilibrium]
     - H₃O⁺(aq): 0
     - CH₃COO⁻(aq): [Initial]
   - **Change in Concentrations (M):**
     - Change due to reaction.
   - **Equilibrium Concentrations (M):**
     - Use changes to find equilibrium concentrations.

**ICE Table Setup:**

| Reactant/Product | CH₃COOH(aq) | H₂O(l)     | ⇌ | H₃O⁺(aq)   | CH₃COO⁻(aq)  |
|------------------|-------------|------------|---|------------|--------------|
| Initial (M)      |             |            |   |            |              |
| Change (M)       |             |            |   |            |              |
| Equilibrium (M)  |             |            |   |            |              |

**Next Steps:**

1. Calculate pH using equilibrium concentrations.
2. Use the buffer equation and equilibrium data to confirm calculations.

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Transcribed Image Text:**Instruction:** **Determine the pH of a buffer formed by dissolving 20.0 g NaCH₃COO into a 500.0 mL solution of 0.150 M of CH₃COOH. Assume the volume of the solution does not change. The value of Ka for CH₃COOH is 1.8 × 10⁻⁵.** **Buffer Preparation Steps:** 1. **Calculate Molarity of NaCH₃COO:** - Dissolve 20.0 g NaCH₃COO in a 500.0 mL solution. - Determine moles and convert to molarity. 2. **Use ICE Table to calculate equilibrium concentrations:** - **Initial Concentrations (M):** - CH₃COOH(aq): [Initial] - H₂O(l): [Pure Liquid, not included in equilibrium] - H₃O⁺(aq): 0 - CH₃COO⁻(aq): [Initial] - **Change in Concentrations (M):** - Change due to reaction. - **Equilibrium Concentrations (M):** - Use changes to find equilibrium concentrations. **ICE Table Setup:** | Reactant/Product | CH₃COOH(aq) | H₂O(l) | ⇌ | H₃O⁺(aq) | CH₃COO⁻(aq) | |------------------|-------------|------------|---|------------|--------------| | Initial (M) | | | | | | | Change (M) | | | | | | | Equilibrium (M) | | | | | | **Next Steps:** 1. Calculate pH using equilibrium concentrations. 2. Use the buffer equation and equilibrium data to confirm calculations. **Navigation Panel:** - 1 / 2 / 3 / Next
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