Determine the maximum angle for which the light rays incident on the end of the light pipe in the figure below are subject to total internal reflection along the walls of the pipe. Assume the light pipe has an index of refraction of 1.27 and the outside medium is air. |2.00 μm

Consider a fiber like the one sketched below. Take the index of refraction of the core to be n₁ = 1.52 and the index of refraction of the cladding to be n₂ = 1.46. A) What is the critical angle for the core/cladding interface? B) If the input angle from air is 00= 10° Calculate 01. C) If the input angle from air is 80-10° Calculate y. D) If the input angle from air is 00=10° will the ray be guided by the fiber with low loss? E) If the input angle from air is 00=30° Calculate 0₁. F) If the input angle from air is 00=30° Calculate y. G) If the input angle from air is 00=30° will the ray be guided by the fiber with low loss? H) What is the maximum input angle from air for a ray that will be guided with low loss by this fiber?

As shown below, light from a vacuum is incident on a shard of Shawtonium (a newly discovered compound). The backside of the shard is up against an unknown material. When the light strikes the backside of the shard, total internal reflection occurs. The light then emerges from the side of the shard and resumes traveling through a vacuum. The index of refraction of Shawtonium is 2.5. Determine 01 & 02 unknown 0₂ shard vacuum 79° 30° 0₁ 0₁ = 0₂=

We know that the index of refraction of materials can help identify those materials. A light beam is shined onto a surface a reflected ray and is found to be completely polarized when the angle of incidence is 53.5°.(a) What is the index of refraction of the reflecting material? (b) What is the angle of refraction if some light passes through the surface of the material?°