Determine the Laurent series of f(z) = (1 + z)/(z^2+z^6) in powers of z that converges for 0 < |z| < 1.

The series from n=0 to infinity of [8^n/(9^n+6)] is given.  Using the direct comparison test, determent the convergence of divergence of the series.

Find the interval of convergence of the power series, where k is a positive integer Σ n = 1 k(k+1)(k + 2) (k+n-1)x^ n!

at) Find all the values of x such that the given series would converge. (-1)(x^)(n+ 4) (9) " The series is convergent from x = to x = n=1 , left end included (enter Y or N): right end included (enter Y or N):