Determine the Kb for cocaine (a base) by constructing an ICE table and using this information to construct and solve the equilibrium constant expression. Complete Parts 1-2 before submitting your answer. PREV 1 2 Based on your ICE table (Part 1) and the definition of Kb, set up the expression for Kb. Each reaction participant must be represented by one tile. Do not combine terms. Once the expression is constructed, solve for the Kb of this base. Kb = = RESET [0] [6.1 × 10-4] [9.60] [2.5 × 10-10] [4.0 × 10-5] [2.1 × 10-4] [5.7 × 10-4] 1 × 10-14 0.050 2.0 × 101 2.8 × 10-6 Determine the Kb for cocaine (a base) by constructing an ICE table and using this information to construct and solve the equilibrium constant expression. Complete Parts 1-2 before submitting your answer. 2 NEXT > The pH for 6.1 × 10-4 M solution of cocaine, a weak base, is 9.60. Let cocaine be represented by the generic base, B. Fill in the ICE table with the appropriate value for each involved species to determine the unknown concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) B(aq) + H₂O(1) = OH-(aq) + BH+(aq) RESET -9.60 2.5 x 10-10 -2.5 × 10-10 4.0 × 10-5 0 6.1 × 10-4 9.60 -4.0 × 10-5 2.1 × 10-4 -2.1 × 10-4 5.7 × 10-4 -5.7 × 10-4
Determine the Kb for cocaine (a base) by constructing an ICE table and using this information to construct and solve the equilibrium constant expression. Complete Parts 1-2 before submitting your answer. PREV 1 2 Based on your ICE table (Part 1) and the definition of Kb, set up the expression for Kb. Each reaction participant must be represented by one tile. Do not combine terms. Once the expression is constructed, solve for the Kb of this base. Kb = = RESET [0] [6.1 × 10-4] [9.60] [2.5 × 10-10] [4.0 × 10-5] [2.1 × 10-4] [5.7 × 10-4] 1 × 10-14 0.050 2.0 × 101 2.8 × 10-6 Determine the Kb for cocaine (a base) by constructing an ICE table and using this information to construct and solve the equilibrium constant expression. Complete Parts 1-2 before submitting your answer. 2 NEXT > The pH for 6.1 × 10-4 M solution of cocaine, a weak base, is 9.60. Let cocaine be represented by the generic base, B. Fill in the ICE table with the appropriate value for each involved species to determine the unknown concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) B(aq) + H₂O(1) = OH-(aq) + BH+(aq) RESET -9.60 2.5 x 10-10 -2.5 × 10-10 4.0 × 10-5 0 6.1 × 10-4 9.60 -4.0 × 10-5 2.1 × 10-4 -2.1 × 10-4 5.7 × 10-4 -5.7 × 10-4
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter16: Principles Of Chemical Reactivity: The Chemistry Of Acids And Bases
Section: Chapter Questions
Problem 125SCQ
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