Determine the Ka of each solution of Acetic acid with its given pH                           1.00 M                    0.100 M                   0.0100M      pH ___2.65____          __3.08_____          ___3.38___      Ka __________            __________             __________   Average Ka  _______________________________

Equal molar amounts of benzoic acid and sodium acetate are mixed together in water, is the resulting solution acid,basic, or neutral? Here are some Ka values

d Hints 11 of 19 I Review | Constants | Periodic Table Part A Rank the solutions in order of decreasing H30. Rank solutions from largest to smallest hydronium ion concentration. To rank items as equivalent, overlap them. > View Available Hint(s) Reset Help 0.10 М НBг 0.10 M HC6H50 0.10 M HF 0.10 М НCIО Smallest concentration Largest concentration

QUESTION 4 Kb (NH3)-1.8 x 10-5 If we mix 20.0 ml of 0.40 M NH3 with 40.0 ml of 0.20 M HCL, the solution pH will be equal to notations) QUESTION S at equilibrium. (type your answer, do not use scientific Ka (HF) 7.2 x 104 Now we mix 15.0 ml of 0.24 M HF and 15.0 ml of 0.24 M NaOH. At equilibrium, the pH of the mixture will be equal to (type your answer, do not use scientific notations)

A solution of a weak acid is 0.20 M and is 0.76 % ionized. Determine Ka.

After calculating the PH of a .66M solution of NH3 Ki for NH3 = 1.9x10-5 and PH is 11.5 Question: Calculate the PH of a solution that is .66 moles I. NH3 and .5 moles in NH4Cl Ki for NH3= 1.9x10-5

Change the top option to a Base and repeat the table for 0.001, 0.01, 0.1 and 1 for the base filling in the table below. Acid Base Initial pH Initial pH Concentration Concentration 0.001M 3.00 0.001M 11.00 0.01M 2.00 0.01M 12.03 0.1M 1.00 0.1M 13.00 1M 0.00 1M 14.00 If you were to use a calculator to do these calculations would you get the same answers? Try at least one on the acid side and one on the base side to confirm your answer.

Based on the ion-product constant, calculate the concentration of OH- ions if the concentration of H+ ions in a given solution is 2.67 x 10^(-5) M.  A. 2.67x10-5 B. 2.67x109 C.3.74x10-10 D. none

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