College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Determine the formula for the partly filled capacitor Cfilled =
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Step 1: Introduce the formula of capacitance
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- Determine the equivalent capacitance for the group of capacitors in the drawing. Let all capacitors be the same where C = 10.0 μFarrow_forwardFind the following. (In the figure, use C, = 31.00 µF and C, = 25.00 µF.) 6.00 µF C2 µF CµF 9.00 V (a) the equivalent capacitance of the capacitors in the figure above uF (b) the charge on each capacitor on the right 31.00-µF capacitor on the left 31.00-µF capacitor μC on the 25.00-µF capacitor on the 6.00-µF capacitorarrow_forwardFind the following. (In the figure use C1 = 37.80 µF and C2 = 31.80 µF.) (a) the equivalent capacitance of the capacitors in the figure above µF(b) the charge on each capacitor on the right 37.80 µF capacitor µC on the left 37.80 µF capacitor µC on the 31.80 µF capacitor µC on the 6.00 µF capacitor µC (c) the potential difference across each capacitor on the right 37.80 µF capacitor V on the left 37.80 µF capacitor V on the 31.80 µF capacitor V on the 6.00 µF capacitor Varrow_forward
- Figure shows a parallel-plate capacitor with a plate area A = 7.89 cm² and plate separation d = 4.62 mm. The top half of the gap is filled with material of dielectric constant k₁ 11.0; the bottom half is filled with material of dielectric constant K₂ = 12.0. What is the equivalent capacitance of the system?arrow_forwardRank order the equivalent capacitances of each of these four groups of capacitors -- all shown capacitors are identical. 00 A В HHHE HE The group of capacitors with the largest equivalent capacitance is [ Select ] The group with the second largest equivalent capacitance is [ Select ] The group with the third largest equivalent capacitance is [ Select ] The group with the smallest equivalent capacitance is [ Select ]arrow_forwardfor the following 26muF capacitor arrangement, find the equivalent capacitance.arrow_forward
- Derive an expression for the capacitance of two concentric hollow spherical conductors of radii r and R. What value do you get for the capacitance when r=4.5 m and R=29.25 m?arrow_forwardIs it always possible to reduce a combination of capacitors to one equivalent capacitor with the rules developed in this chapter? Explain.arrow_forwardWhat total capacitances (in uF) can you make by connecting a 5.60 mF and an 8.90 MF capacitor together? smaller value uF larger value uFarrow_forward
- Determine the equivalent capacitance of if C1 = 600 mF and C2 = 800 mF are in series, and together they are in parallel with C3 = 1000 mF. Give the answer in mF.arrow_forwardA spherical capacitor with a 0.600 mm gap between the spheres has a capacitance of 150 pF Part A What is the diameter of the smaller sphere? ΠV ΑΣφ Dymal = Submit Request Answer gap rin Part B What is the diameter of the larger sphere? HV ΑΣφ rout Diere = Submit Request Answerarrow_forwardConsider the following. (Let C1 = 13.00 µF and C2 = 7.00 µF.) a) Find the equivalent capacitance of the capacitors in the figure. µF(b) Find the charge on each capacitor. on the right 13.00 µF capacitor µC on the left 13.00 µF capacitor µC on the 7.00 µF capacitor µC on the 6.00 µF capacitor µC (c) Find the potential difference across each capacitor. on the right 13.00 µF capacitor V on the left 13.00 µF capacitor V on the 7.00 µF capacitor V on the 6.00 µF capacitorarrow_forward
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