Determine the following of the truss shown using the method of consistent deformations: Answer: Horizontal Support Reaction lat A= k Axial force in member BF= Axial force in member DF= Vertical Support Reaction at D= E (6 in.2) F A, (6 in.²) (6 in.2) (4 in.²) (4 in.²) B (4 in.2) (6 in.²) 25 k 25 k -3 panels at 20 ft = 60 ft- E = 29,000 ksi C -28 k (6 in.2) (6 in.2) k k k D tp. 15 ft Dx

Part 2,3,4

Please solve this question in hand wirting step by step.

A bronze pipe (1) is to be connected to an aluminum alloy pipe (2) at flange B. When put in place, however, a gap of A = 0.35 in. exists between the two pipes. Bronze pipe (1) has an elastic modulus of E1 = 16,000 ksi, a cross-sectional area of A1 = 2.66 in.?, and a length of L1 = 6.7 ft. Aluminum alloy pipe (2) has an elastic modulus of E2 = 10,000 ksi, a cross-sectional area of A2 = 1.37 in.2, and a length of L2 = 10.2 ft. If bolts are inserted in the flanges and tightened so that the gap at B is closed, determine: (a) the normal stresses produced in each of the members. (b) the final position of flange B with respect to support A. L2 В (1) Answer: (a) 01 = ksi 02 = ksi (b) ÕB/A = in.

Problem 2 The rigid bar is plnned at A and held by two flexible bars at E and C. The load P Is applled at B. The two flexible bars FE and DC each have a diameter of 1 In. The flexible bars are elastic- perfectly plastic with a yleld stress equal to 20 ksl and a yleld strain of 0.001. Determine the following: The load R, at first yleld and the corresponding deflection at B, &, The ultimate load Pu and the corresponding deflection du The permanent deflection and residual stresses in each rod if the ultimate load is removed Construct P - A curve showing yield, ultimate and permanent deformation o (ksi) 1 ft E F 1 ft1 ft 20 B P e (in./in.) 0.001 1 ft D 2 ft 1 ft A

A rod is composed of 3 segments shown in the figure and carries the axial loads, P1=120KN and P2=50KN. If the walls are rigid, determine the stress of bronze, aluminum, and steel in MPa.