Determine the energy, in J, of a photon with a wavelength of 311 nm. (h = 6.626 x 10-34 J.s and c = 3.00 x 10³ m/s)

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**Question: Determine the energy, in joules (J), of a photon with a wavelength of 311 nm.**

**Constants:**
- Planck's constant \( h = 6.626 \times 10^{-34} \, \text{J s} \)
- Speed of light \( c = 3.00 \times 10^8 \, \text{m/s} \)

To calculate the energy of a photon, use the formula:

\[ E = \frac{h \cdot c}{\lambda} \]

Where:
- \( E \) is the energy of the photon in joules.
- \( h \) is Planck’s constant.
- \( c \) is the speed of light.
- \( \lambda \) is the wavelength in meters. (Note: Convert 311 nm to meters for calculation.)

1. Convert the wavelength from nanometers to meters:
   - \( \lambda = 311 \, \text{nm} = 311 \times 10^{-9} \, \text{m} \)

2. Substitute the values into the formula and calculate \( E \).
Transcribed Image Text:**Question: Determine the energy, in joules (J), of a photon with a wavelength of 311 nm.** **Constants:** - Planck's constant \( h = 6.626 \times 10^{-34} \, \text{J s} \) - Speed of light \( c = 3.00 \times 10^8 \, \text{m/s} \) To calculate the energy of a photon, use the formula: \[ E = \frac{h \cdot c}{\lambda} \] Where: - \( E \) is the energy of the photon in joules. - \( h \) is Planck’s constant. - \( c \) is the speed of light. - \( \lambda \) is the wavelength in meters. (Note: Convert 311 nm to meters for calculation.) 1. Convert the wavelength from nanometers to meters: - \( \lambda = 311 \, \text{nm} = 311 \times 10^{-9} \, \text{m} \) 2. Substitute the values into the formula and calculate \( E \).
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