Determine the design flexural strength in ft kips of a W10X26 of A242 (Fy = 50ksi) steel subject to a. Continuous lateral support. Blank 1 b. An unbraced length of 10 ft with Cb = 1.0. Blank 2 C. An unbraced length of 20 ft with Cb = 1.0. Blank 3 W10x26 A =| 7.61 in.42 d = 10.300 in. tw = 0.260 in. bf = 5.770 in. tf = 0.440 in. T= 8-1/4 in. k = 0.7400 in. k1 = 0.6875 in. gage = 2-3/4 in. rt = 1.540 in. d/Af = Ix = Sx = 4.07 144.00 in.^4 27.90 in.43 4.350 in. ly = Sy = 14.10 in.4 4.89 in.43 ry = 1.360 in. Zx = 31.3 in.43 Zy = 7.50 in.43 J = 0.40 in. ^4 Cw = 345 in 6 a = 47.14 in. Wno = 14.30 in.^2 Sw = Qf = 9.05 in.4 5.99 in.43 Qw = 15.50 in.43 II ||

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Determine the design flexural strength in ft kips of a W10X26 of A242 (Fy = 50ksi) steel subject to
a. Continuous lateral support. Blank 1
b. An unbraced length of 10 ft with Cb = 1.0. Blank 2
C. An unbraced length of 20 ft with Cb = 1.0. Blank 3
W10x26
A =
...
7.61
in.^2
d =
10.300
in.
tw =
0.260
in.
bf =
5.770
in.
tf =
0.440
in.
T=
8-1/4
in.
k =
0.7400
in.
k1 =
0.6875
in.
gage =
2-3/4
in.
rt =
d/Af =
Ix =
Sx =
1.540
in.
4.07
144.00
in.^4
27.90
in.^3
rx =
4.350
in.
ly =|
14.10
in 4
S =
4.89
in.^3
ry =
1.360
in.
Zx =
31.30
in.43
Zy =
7.50
in 43
J =
0.40
in.^4
Cw =
345
in.^6
a =
47.14
lin.
Wno =
14.30
in.^2
9.05
Sw =
Qf =
in.4
5.99
in.43
Qw =
15.50
in.^3
I|||
I|||
Transcribed Image Text:Determine the design flexural strength in ft kips of a W10X26 of A242 (Fy = 50ksi) steel subject to a. Continuous lateral support. Blank 1 b. An unbraced length of 10 ft with Cb = 1.0. Blank 2 C. An unbraced length of 20 ft with Cb = 1.0. Blank 3 W10x26 A = ... 7.61 in.^2 d = 10.300 in. tw = 0.260 in. bf = 5.770 in. tf = 0.440 in. T= 8-1/4 in. k = 0.7400 in. k1 = 0.6875 in. gage = 2-3/4 in. rt = d/Af = Ix = Sx = 1.540 in. 4.07 144.00 in.^4 27.90 in.^3 rx = 4.350 in. ly =| 14.10 in 4 S = 4.89 in.^3 ry = 1.360 in. Zx = 31.30 in.43 Zy = 7.50 in 43 J = 0.40 in.^4 Cw = 345 in.^6 a = 47.14 lin. Wno = 14.30 in.^2 9.05 Sw = Qf = in.4 5.99 in.43 Qw = 15.50 in.^3 I||| I|||
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