Determine the capacitance of diffused junction varactor at a reverse potential of 4.5 V. if C(0) = 85 pF and V₁ = 0.7 V. Also determine the value of K.
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Determine the capacitance of diffused junction varactor at a reverse potential of 4.5 V. if C(0) = 85 pF and V₁ = 0.7 V. Also determine the value of K.
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- What voltage is boosted at the output of a multiplier.Choices: average, rms, peak, or instantaneous Which assumption is not used in the analysis of multipliers?Choices: a capacitor will not discharge, start with the cycle of the source that will forward bias the nearest diode, the output will always be multiplied, or a single diode is forward biased at a time A voltage multiplierChoices: multiplies the output voltage, has very high voltage and low current ,can employ inductors, or may not have equal numbers of diodes and capacitors A voltage regulator maintains constant voltage at the load regardless of variations atChoices: the input and output, the load, source, or in the environment Between a lower percent regulation and a higher one, which is better?Choices: lower or higherFor the given circuit for a 4O V (p-p) sinusoidal input vi, what is the value of vi at which the clipping begins? V=5V. NOTE: use ideal diodeStep-down chopper circuit connected to 100V d.c source supplies with inductive of 40mH the load resistive of 5Q, and a freewheeling diode is placed to the load . the load current varies between 12A and 16A, determine time ratio of the chopper.
- Question 1: In the circuit shown below, the output (Vo = 10V Max.) Unipolar. The frequency of Primary is 60 Hz. The diodes are Silicon with VD = 0.7V. a. Sketch the output without a Capacitor. b. Determine Voc without a Capacitor. c. Sketch Vs (at the Secondary). d. Determine Voc with a Capacitor of 10 uF across RL. e. Determine the RMS Value of Vp (at the Primary). f. PIV (Peak Inverse Voltage). 10:1 Output C. 22 k1 All diodes are IN4001. | 000004) Determine the value of branch current, I1 and I25) Determine the value of voltage across resistor, R1, R2 and R36) Determine the value of voltage across capacitor, C1 and C27) Determine the value of voltage across inductor, L.Full-wave rectified sine wave circuit is used to measure the RMS value of a half square wave with the help of PMMC meter. The meter was actually calibrated for sine wave. The circuit uses a meter movement with a full scale deflection current of 200uA and internal meter resistance of 5kΩ. Assuming Non-ideal diodes having resistance 1kΩ, Analyze the circuit to determine the value of series multiplier resister and the corrected RMS voltage, if meter is to read 225V RMS full-scale.
- a) For the following input and Vm = 15V and V = 5V: find and draw vo. Consider the diode as an Ideal Diode. [Instructions: Mark ON/OFF interval on the input waveform; Draw equivalent circuits for ON/OFF state; Draw vo on the same vertical axis of vi] b) If a square wave input with Vpp = 20V is applied instead of the sinusoid, find and draw vo. Consider the diode as an Ideal Diode. [Instructions: Mark ON/OFF interval on the input waveform; Draw equivalent circuits for ON/OFF state; Draw v, on the same vertical axis of v,] Vi R Vm Vi + -VmA clipper circuit based on diodes are simple way to modify waveform in mechatronics. Assume that the two diodes shown in the circuit below are ideal diodes. If the input voltage in the circuit is a 1 kHz sinusoid with peak amplitude of 8V, sketch the Vaue (t). 10 k. 8V 10 kN. D2 RL Vourlt) Vin= Vin(t) Ims D1 6V -8V 4V Page | 1For the given circuit for a 40 V (p-p) sinusoidal input vi, what is the value of vi at which the clipping begins? V=5V. NOTE: use * ideal diode 25 3 5 v -20 Clipping doesn't occur
- The current through the diode in the circuit given in the Figure below when Vy = 0.7 V is? ww 8092 12V Select one a. 24.26 mA b. 13.09 mA c. 58.23 mA d. 40.13 mA 40-52 ww 3092 IDDetermine the forward voltage and forward current of a diode in a circuit. The circuit is composed of a dc voltage source with its positive terminal of 10V connected in series to a 1Kohms resistor and the anode of a diode. The cathode of the diode is connected to ground. Use ideal device model approach. Draw the circuit and show your solution/s.A clipper circuit based on diodes are simple way to modify waveform in mechatronics. Assume that the two diodes shown in the circuit below are ideal diodes. If the input voltage in the circuit is a 1 kHz sinusoid with peak amplitude of 8V, sketch the Va.. (t) 10 kO 8V 10 kO Vin Vin(t) D2 Vout(t) RL Ims D1 6V -8V 4V Page | 1