Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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- f = *This formula is to find the M * C I Compound stresses O Shear stresses O Flexural stresses O Torsion stresses Oarrow_forwardQ2 - The assembly shown below consists of three rods AB, CD and EF with the following properties: AB and CD: Modulus of elasticity = 75 GPa; Diameter = 30 mm EF: Modulus of elasticity = 200 GPa; Diameter = 15 mm If there is a 0.5 mm gap at A and C before loading, Determine the average normal stress developed in rods AB, CD and EF. Note: The cap GH is rigid. 0.5 mm -250 mm A C 30 mm 30 mm B D H G E 500 mm 50 kN 50 kN 15 mm Farrow_forwardPlz complete solution.arrow_forward
- The point loads are placed at the fixed positions shown in the figure and they are live loads. A k a b a b dn = 1₂ Icr= M B 7 Ast Stress profile (concrete) Cross section before cracking Aso Cross section Asc Ast N.A. Q2) Now, the live load increases gradually and the moment at the critical section just exceeds the cracking moment (Mcr), but the compressive section of the concrete is still under the linear elastic region. Please be reminded that in the flexural design, the crack of the concrete section starts where the tensile stress reaches the tensile strength. It is assumed that the cracks then propagate rapidly up to the entire tension section (up to the neutral axis) and this cracked concrete section cannot resist the tension. It should be noted that in reality, concrete sections between the primary cracks can still resist some tensile stresses as shown in the figure, which should be considered in the displacement design. However, in flexure design, we design the critical section…arrow_forwardThe aluminum bar ACDB is rigidly connected to a steel tube in CD. The data is presented in the table. If the load P is equal to 125 kN, determine: The stress of aluminum in segment AC. Answ: 63.66 MPa The stress of aluminum in segment CD. Answ: 13.93 MPa The stress in steel in segment CD. Answ: 39.79 MPa The total deformation of the bar. Answ: 0.29273 mmarrow_forwardAs shown, an aluminium alloy construction BCD with a circular cross section is fixed at end B and affected by a force of 150 N at the free end D. The diameter of the cross-section a-a is 20 mm. The yield strength of the material is 80 MPa: a) Determine the stresses at point A of the a-a cross-section. As indicated in the picture, draw the stress element in Cartesian coordinates and specify the stress values.(b) Calculate the factor of safety, n for Tresca, and the von Mises yield criterion to see if the structure would yield based on the stresses at point A.(c) In the major stress area, draw the yield loci of both criteria and indicate the operational stress state & why is the Rankine failure criterion inappropriate for aluminium alloys?arrow_forward
- In the marine crane link CD is has a uniform cross section of 50 x 150 mm and a modulus of 200 GPa. Determine the axial stress and change in length of link CD. Reference: Beer, et.al., 7th Edition Mechanics of Materials 35 m 15 m C D -15 m A -25 m. B 3 m 80 Mgarrow_forwardConsider the compound system consisting of three sections with cross-sectional areas 3A, 2A, and A and loaded as shown. Which of the following gives the maximum average normal stress in the system shown? 6P 4P A5.5 P/A B.4.5 P/A 3A 2A A 3P C.4 P/A D.3 P/A 4P 6P Which of the following is the highest value of stress within the strain hardening region of a typical elasto-plastic material subjected to tensile test? A. Elastic Limit B.Yield Stress C.Ultimate Stress D.Proportional Limit What is the lateral strain of a uniaxially loaded member if its longitudinal strain is 0.02 and its Poisson's ratio is equal to 0.3? A.+0.006 B.-0.006 C.+0.667 D.-0.667 Which of the following is the highest value of stress within the elastic region of a typical elasto-plastic material subjected to tensile test? A.Yield Stress B.Elastic Limit C.Ultimate Stress D.Proportional Limitarrow_forward#2 will upvote to anyone who will answerarrow_forward
- Please explain the steps with the solutionarrow_forwardA uniform edge load of w₁ = 540 lb/in. and W2 = 400 lb/in. is applied to the polystyrene specimen. Ep = 597 (10³) psi and vp = 0.25. (Figure 1) Figure T W₂ b - < 1 of 1arrow_forwardThe solid circular drill rod AB is made of a steel that is assumed to be elastoplastic with τY = 22 ksi and G = 11.2 × 106 psi. Knowing that a torque T = 72 kip·in. is applied to the rod and then removed, determine the maximum residual shearing stress in the rod. The maximum residual shearing stress in the rod is ksi.arrow_forward
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