Determine the avevage power delivered to a network having the following input voltage and Current: V(+) = 100 sin (20π + + 40°) i(t) = 20 Sin (20πt - 30°)

An uncharged capacitor and a resistor are connected in series to a source of emf. If  = 8.00 V, C = 25.0 µF, and R = 100 Ω, find the following. (a) the time constant of the circuit Your response is off by a multiple of ten. ms(b) the maximum charge on the capacitor µC(c) the charge on the capacitor at a time equal to one time constant after the battery is connected µC

In the circuit diagram R1 = 5R and R2 = 15R, where R = 14 Ω. The power dissipated in resistor 2 is P = 1.6 W.  Part (a)  What is the voltage across the battery in volts?  Part (b)  How much power, Ps, is the source supplying, in watts?

Two capacitors in the circuit shown is C1= 7.5 µF and C 2=12.5 µF connected to two resistors is R1 = 5 kn and R2 = 7 kn and the battery emf is AV= 350 V (a) Calculate the time constant, (b) Calculate the maximum charge the Qmax capacitor could acquire, (c) Find time, it takes for the capacitance charge Q(t) to reach 68 % of the maximum charge Qmax- (d) Plot the current I when the charge Q(t) respect to time (t) R1 C C, HHI R2 AV S