Determine id Jhe follo wiyp series Converpes or Yntearel Test. Show oliverpes using The your work carefule

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Problem Statement

**2) Determine if the following series converges or diverges using the Integral Test. Show your work carefully and detailed.**

\[ \sum_{n=1}^{\infty} \frac{e^{1/n}}{n^2} \]

### Detailed Explanation

#### Integral Test

To apply the Integral Test, we need to check if \( f(x) = \frac{e^{1/x}}{x^2} \) is continuous, positive, and decreasing for \( x \geq 1 \). 

**Step 1: Verify if \( f(x) \) is continuous, positive, and decreasing**

- **Continuity**: \( e^{1/x} \) is continuous for all \( x \neq 0 \) and \( x^{-2} \) is continuous for \( x \neq 0 \). Hence, \( f(x) \) is continuous for \( x \geq 1 \).
- **Positivity**: \( e^{1/x} > 0 \) and \( x^{-2} > 0 \) for \( x \geq 1 \), thus \( f(x) > 0 \) for \( x \geq 1 \).
- **Decreasing**: To check if \( f(x) \) is decreasing, we can find the derivative \( f'(x) \) and see if it is less than or equal to 0 for \( x \geq 1 \).

**Step 2: Find \( f'(x) \)**

Let \( f(x) = \frac{e^{1/x}}{x^2} \).

Using the quotient rule for derivatives:

\[ f'(x) = \frac{d}{dx} \left( \frac{e^{1/x}}{x^2} \right ) = \frac{(e^{1/x})' \cdot x^2 - e^{1/x} \cdot (x^2)'}{(x^2)^2} \]

First, calculate \( (e^{1/x})' \):

\[ (e^{1/x})' = e^{1/x} \cdot \left( \frac{d}{dx} \left( \frac{1}{x} \right) \right) = e^{1/x} \cdot \left( -\frac{1}{
Transcribed Image Text:### Problem Statement **2) Determine if the following series converges or diverges using the Integral Test. Show your work carefully and detailed.** \[ \sum_{n=1}^{\infty} \frac{e^{1/n}}{n^2} \] ### Detailed Explanation #### Integral Test To apply the Integral Test, we need to check if \( f(x) = \frac{e^{1/x}}{x^2} \) is continuous, positive, and decreasing for \( x \geq 1 \). **Step 1: Verify if \( f(x) \) is continuous, positive, and decreasing** - **Continuity**: \( e^{1/x} \) is continuous for all \( x \neq 0 \) and \( x^{-2} \) is continuous for \( x \neq 0 \). Hence, \( f(x) \) is continuous for \( x \geq 1 \). - **Positivity**: \( e^{1/x} > 0 \) and \( x^{-2} > 0 \) for \( x \geq 1 \), thus \( f(x) > 0 \) for \( x \geq 1 \). - **Decreasing**: To check if \( f(x) \) is decreasing, we can find the derivative \( f'(x) \) and see if it is less than or equal to 0 for \( x \geq 1 \). **Step 2: Find \( f'(x) \)** Let \( f(x) = \frac{e^{1/x}}{x^2} \). Using the quotient rule for derivatives: \[ f'(x) = \frac{d}{dx} \left( \frac{e^{1/x}}{x^2} \right ) = \frac{(e^{1/x})' \cdot x^2 - e^{1/x} \cdot (x^2)'}{(x^2)^2} \] First, calculate \( (e^{1/x})' \): \[ (e^{1/x})' = e^{1/x} \cdot \left( \frac{d}{dx} \left( \frac{1}{x} \right) \right) = e^{1/x} \cdot \left( -\frac{1}{
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