Determine a wrench equivalent force system and specify the x and y coordinates of the point where the wrench's line of actionintersects the xy plane. Take the value of M₁ to be 4.6 N·m and M2 to be 6.6 N-m.0.8 my1 mM1M210 NxThe value of FR of the wrench equivalent force system isThe value of MR of the wrench equivalent force system isThe line of action of the wrench intersects the xy plane at x=The line of action of the wrench intersects the xy plane at y =k) N.) N.m. (Round the final answer to one decimal place.)m. (Round the final answer to two decimal places.)m.

Answered: Determine a wrench equivalent force…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter7: Gravity

Section: Chapter Questions

Problem 56PQ: Consider the Earth and the Moon as a two-particle system. a. Find an expression for the...

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Replace the 22-kN force acting at point A by a force-couple system at (a) point O and (b) point B. At each point, give the magnitudes of the resultant force and moment. The moment is positive if counterclockwise and negative if clockwise. 22 KN 36⁰° Answers 4.5 m (a) Point O: F= (b) Point B: F= | Mi i 8.5 m B kN, Mo= i kN, MB = M kN.m kN-m
solve mcq number 8 and give answer from any four of the following
Learning Goal: To understand how to quantitatively determine whether a particle is in a state of mechanical equilibrium. As shown, three forces, F1, F2, and F3, act at the same point on an object. (Figure 2) The point of application is the origin of a Cartesian coordinate system. F1, which has a magnitude of F1 = 20.0 kN , is in the y-z plane and is described by an angle B1 = 34.0 degrees . F2 is in the x-z plane and is described by integer lengths of a similar right triangle; its magnitude is F2 = 25.0 kN. If the sum of the forces is equal to zero, what is the magnitude of F3? Express your answer numerically in kilonewtons to three significant figures. In statics, we make extensive use of Newton's first law, which states that a particle, initially at rest, or moving in a straight line with constant velocity, will remain in its current state unless the particle is subjected to an unbalanced force system. If the sum of the forces acting on a particle is zero, then it is in mechanical…
For the given force system: Each square is 1 m by 1 m. Mr= 509.061 N-m (clockwise) Rx= -1027.68 N RY3D -445.98 N P. X. (a) Calculate the value of P [ Select] (b) Calculate the value of Q [ Select ] (c) Calculate the value of F [ Select] (d) Determine moment arm of the resultant force Select] (e) Determine equation of the resultant force Select ] (f) Find x and y intercept [ Select]
30 ft _6 ft- 5 ft B ft The boy pulls on the rope with a force of 80 lb.
of Three forces are applied to a bracket as shown. Point A lies at the origin of the xy-axes. F1 = 250 N, F2 = 500 N and F3 =375 N F2 F1 30°f 0.5 m 0.5 m 1 y A B 0.5 m -0.5 m Moment MA = F3 a) Replace the system by an equivalent force-couple system at A. Resultant Force Component in x direction= Resultant Force Component in y direction= 0.3 m- YR measured from A= N.m N b) Determine where the equivalent single force line of action intersects the y-axis measured from A. m N
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Sketch what the problem is asking for.
For the three forces acting on the pole: Calculate the magnitude of the resultant force. F₁ - 75 KN F₂ - 90 KN F₁ - 110 KN XA - 5 m VA 8 m Z-10 m KN ENTER Calculate the resultant moment at O in vector form A (X, YO + Calculate the magnitude of the resultant moment F₂ kN Replace the forces with a Cartesian resultant force vector passing through the origin of the axes (point O). KN.m ENTER K KN F₂KN ENTER D(0,0, Z₂) k kN.m ENTER F,kN B (X, Y₂0) X-6 m X--6m C(X, Y, 0) Ye-8 m Ye -9 m
What will be the cross product of the vectors 2i+3j+k and 6i+9j+3k ? * O i+ 2j + k O i-j- 5k O 2i -j- 5k
From the given figure, determine the rectangular representation of the 500 N force. F = 500 N O a. F = -240 i+ 320j+ 300 k N O b. F = 240 i- 320j - 300 k N O c. F = 560i- 720 j- 20o k N O d. F = 420 i- 230j - 700 k N
6 F=LOKN TE=4KN Express the force F3 needed to keep a particle Oi n equilibrium as a Cartesian vector. * O [oi-2j-8k] O (8i+0j+2k] O 1-8i+0j-2k] O (oi-8j-2k]

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