Design an op amp circuit that can perform the following operations Vout = 16*(dVin/dt) For 3 different inputs, Vout = 4*(V1+ V2+ V3)

Va=3V and Vb=0V so I think that this would result in an inverting op-amp and has the equation -(160/20)*3=-24V but this is wrong I tried the long way as well but got the same answer. The possible source of error could be the 5k resistor but that doesn't make to much sense to me. How do I solve this?

1. Consider the ideal op-amp circuit below. Let Us = 0.1 V, R1 = R2 = R3 = R3 = 100 kN, and R4 = 98 kN, Solve for Vo. R1 RA R5 vo R2 Us R3

OAP 5 Design an op-amp circuit using a single op-amp that adds two input signals V₁1 and Vs2. That is, Vo = Vs1 + Vs2. Each input signal can vary between -5 V and +5 V: -5 V ≤ Vs1 ≤ +5 V and -5 V ≤ Vs2 ≤ +5 V. Choose resistor values such that the maximum current leaving or entering either voltage source (vs1 or Vs2) is 1 mA. (You can assume the power rails VDD and Vss are large enough to accommodate the most extreme outputs.)