Design a 5" thick simply supported reinforced concrete one-way slab as shown in Figure 1. Make the design using a 12”-strip. Work the problem on paper, showing all steps on how the problem was solved. Can you also make sure to have all the numbers with their correct units. 5 in.2wò=15 ¹² + slab weightft2WL= 30¹b/ftnormal weight concretedensity = 150 pcfspan length=8 ft →Normal Weight Concretef'c = 4000 psiGr. 60 steel////Figure 1No. 3 bars (temperature and shrinkage)Maximum center-to-center spacing = ?No. 3 bars (flexural steel)Maximum center-to-center spacing = ?span length =8 ftd = 4 in.

Given data,span=8'h=5"d=4"fc'=4 ksify=60ksiw0=15pcf+slab weigh15+150 x 5/12=77.5 pcfwL=30pcf

Answered: Design a 5" thick simply supported…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Design a 5" thick simply supported reinforced concrete one-way slab as shown in Figure 1. Make the design using a 12”-strip. Work the problem on paper, showing all steps on how the problem was solved. Can you also make sure to have all the numbers with their correct units.

5 in.
2
wò=15 ¹² + slab weight
ft
2
WL= 30¹b/ft
normal weight concrete
density = 150 pcf
span length=8 ft →
Normal Weight Concrete
f'c = 4000 psi
Gr. 60 steel
////
Figure 1
No. 3 bars (temperature and shrinkage)
Maximum center-to-center spacing = ?
No. 3 bars (flexural steel)
Maximum center-to-center spacing = ?
span length =8 ft
d = 4 in.

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